Java 中的数学类方法，带示例|第 2 集

原文:https://www . geesforgeks . org/math-class-methods-Java-examples-set-2/

java.math 类及其方法|集 1

java.math class methods 本文讨论的 java.math 类方法:

  1. ABS():Java . math . ABS()方法返回传递的任何类型参数的绝对值。这个方法可以处理所有的数据类型。 Special Case :

  2. 如果参数为正零或负零，则结果为正零。 如果参数为无穷大，则结果为正无穷大。 Result is NaN, if passed argument is NaN.

    语法:

    ```java public static datatype abs(datatype arg) Parameters: arg - the argument whose absolute value we need Returns: absolute value of the passed argument.

    ```

    • acos():Java . math . acos()方法返回传递的参数的弧余弦值。 弧余弦是传递的参数的反余弦。 acos(arg) = cos -1 的 arg 特例:结果为 NaN，如果自变量为 NaN 或其绝对值大于 1。 语法:
public static double acos(double a)
Parameters:
a - the argument whose arc cosine value we need.
    argument is taken as radian    
Returns:
arc cosine value of the argument.

  • toRadians() : java.math.toRadians(double deg) method converts argument (degree) to radians. Special Point : Math class usually takes radians as an input which is very much different in real life applications since angles is usually represented in degrees. Syntax:

    ```java public static double toRadians(double deg) Parameters: deg - degree angle needs to be in radian. Returns: radians equivalent of the degree-argument passed.

    ```

    什么是 NaN 论证？ 一个持有双精度型非数字值的常数。它相当于 double . longbittodouble(0x7ff 800000000000001)返回的值。

    在 Math 类中解释 abs()、acos()、toRadians()方法的 Java 代码。

    ```java // Java program explaining Math class methods // abs(), acos(), toRadians() import java.math.*; public class NewClass {

    public static void main(String[] args)     {         // Declaring the variables         int Vali = -1;         float Valf = .5f;

    // Printing the values         System.out.println("Initial value of int  : "+Vali);         System.out.println("Initial value of int  : "+Valf);

    // Use of .abs() method to get the absoluteValue         int Absi = Math.abs(Vali);         float Absf = Math.abs(Valf);

    System.out.println("Absolute value of int : "+Absi);         System.out.println("Absolute value of int : "+Absf);         System.out.println("");

    // Use of acos() method         // Value greater than 1, so passing NaN         double Acosi = Math.acos(60);         System.out.println("acos value of Acosi : "+Acosi);         double x = Math.PI;

    // Use of toRadian() method         x = Math.toRadians(x);         double Acosj = Math.acos(x);         System.out.println("acos value of Acosj : "+Acosj);

    } } ```

    输出:

    ```java Initial value of int : -1 Initial value of int : 0.5 Absolute value of int : 1 Absolute value of int : 0.5

    acos value of Acosi : NaN acos value of Acosj : 1.5159376794536454

    ```

    • addExact():Java . math . addExact(int a，int b) 方法返回传递的参数之和。 特殊点:如果 Result 溢出一个 int 或 long(根据传递的参数)，则方法抛出 ArithmeticException。 语法:

    ```java public static int addExact(int x, int y) or public static long addExact(long x, long y) Parameters: a - first value b - second value Returns: Sum of the specified method arguments - a and b.

    ```

    • asin() : java.math.asin() method returns the arc sine value of the method argument passed. Returned angle is in the range -pi/2 to pi/2. arc sine is inverse sine of the argument passed. asin(arg) = sine-1 of arg Special Case :
    • 如果参数为 NaN 或其绝对值大于 1，则结果为 NaN。
    • 如果参数为零，则结果为零。

    语法:

    ```java public static double asin(double arg) Parameters: arg - argument passed. Returns: arc sine of the argument passed.

    ```

    • cbrt():Java . math . cbrt()方法返回传递的参数的立方根。 特殊点:

  • 结果是 NaN，如果参数是 NaN。

  • 如果参数是无限的，则结果是一个与参数符号相同的无穷大。
  • 如果参数为零，则结果为零。

语法:

public static double cbrt(double arg)
Parameters:
arg - argument passed. 
Returns:
cube root of the argument passed

在 Math 类中解释 addExact()、asin()、cbrt()方法的 Java 代码。

// Java program explaining Math class methods
// addExact(), asin(), cbrt()
import java.math.*;
public class NewClass
{

    public static void main(String[] args)
    {
        int a = 1, b = 8;

        // get the result of addExact method
        int radd = Math.addExact(a,b);
        System.out.println("Using addExact() : "+radd);
        System.out.println("");

        // Use of acos() method
        // Value greater than 1, so passing NaN
        double Asini = Math.asin(radd);
        System.out.println("asin value of Asini : "+Asini);
        double x = Math.PI;

        // Use of toRadian() method
        x = Math.toRadians(x);
        double Asinj = Math.asin(x);
        System.out.println("asin value of Asinj : "+Asinj);
        System.out.println("");

        // Use of cbrt() method
        double cbrtval = Math.cbrt(216);
        System.out.println("cube root : "+cbrtval);

    }
}

输出:

Using addExact() : 9

acos value of Asini : NaN
acos value of Asinj : 0.054858647341251204

cube root : 6.0

  • floor():Java . math . floor()方法返回参数的 floor 值，即小于或等于传递的参数的最接近的整数值。 例如:101.23 的地板值= 101 重要一点:如果通过了安南或无限参数，则会产生相同的参数。

    ```java Syntax: public static double floor(double arg) Parameters: arg - the argument whose floor value we need Returns:closest possible value that is either less than or equal to the argument passed

    ```

    • hypot() : java.math.hypot(double p, double b) method returns hypotenuse of a right triangle on passing the traingle’s base and perpendicular as arguments. hypotenuse = [perpendicular2 + base2]1/2

    要点:

    • 如果任一参数为无穷大，则结果为正无穷大。
    • 如果任一参数为 NaN，且任一参数都不是无穷大，则结果为 NaN。

    ```java Syntax: public static double hypot(double p, double b) Parameters: p - perpendicular of the right triangle b - base of the right triangle Returns: hypotenuse of the right triangle

    ```

    • ieeereminder():Java . math . ieeereminder(double D1，double d2) 方法通过对两个参数应用余数运算返回余数值 w.r.t IEEE 754 标准。 余数=D1–D2 * n 其中， n = D1/D2

    ```java Syntax: public static double IEEEremainder(double d1,double d2) Parameters: d1 - dividend d2 - divisor Returns: remainder when f1(dividend) is divided by(divisor)

    ```

    的最接近精确值 log() : java.math.log()* method returns the logarithmic value of the passed argument.

    ```java Syntax: public static double log(double arg) Parameters: arg - argument passed. Returns: logarithmic value of the argument passed.

    ```

    在 Math 类中解释 floor()，hypot()，IEEEremainder()，log()方法的 Java 代码。

    ```java // Java program explaining MATH class methods // floor(), hypot(), IEEEremainder(), log() import java.lang.*; public class NewClass {

    public static void main(String[] args)     {         // Use of floor method         double f1 = 30.56, f2 = -56.34;         f1 =Math.floor(f1);         System.out.println("Floor value of f1 : "+f1);

    f2 =Math.floor(f2);         System.out.println("Floor value of f2 : "+f2);         System.out.println("");

    // Use of hypot() method         double p = 12, b = -5;         double h = Math.hypot(p, b);         System.out.println("Hypotenuse : "+h);         System.out.println("");

    // Use of IEEEremainder() method         double d1 = 105, d2 = 2;         double r = Math.IEEEremainder(d1,d2);         System.out.println("Remainder : "+r);         System.out.println("");

    // Use of log() method         double l = 10;         l = Math.log(l);         System.out.println("Log value of 10 : "+l);

    } } ```

    输出:

    ```java Floor value of f1 : 30.0 Floor value of f2 : -57.0

    Hypotenuse : 13.0

    Remainder : 1.0

    Log value of 10 : 2.302585092994046

    ```

    java.math 类及其方法|第 3 集

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