使用 Python 中的正则表达式将密码分类为强或弱
原文:https://www . geeksforgeeks . org/category-password-as-strong-or-weak-using-regex-in-python/
给定一个密码，我们必须将其分为强密码或弱密码。要成为强密码，需要满足一些检查。对于弱密码，我们需要返回它弱的原因。
需要满足的条件是:
- 最少 9 个字符，最多 20 个字符。
- 不能是换行符或空格
- 一行中不应有三个或更多重复字符。
- 同一字符串模式(最少两个字符长度)不应重复。
注意:要检查密码的基本验证，请单击此处。
示例:
Input1 : Qggf!@ghf3
Output1 : Strong Password!
Input2 : aaabnil1gu
Output2 : Weak Password: Same character repeats three
or more times in a row
Input3 : Geeksforgeeks
Output3 : Weak Password: Same character repeats three
or more times in a row
Input4 : Aasd!feasnm
Output4 : Weak password: Same string pattern repetition
Input5 : 772*hdf77
Output5 : Weak password: Same string pattern repetition
Input6 : " "
Output6 : Password cannot be a newline or space!
下面是实现。
# Categorizing password as Strong or
# Weak in Python using Regex
import re
# Function to categorize password
def password(v):
# the password should not be a
# newline or space
if v == "\n" or v == " ":
return "Password cannot be a newline or space!"
# the password length should be in
# between 9 and 20
if 9 <= len(v) <= 20:
# checks for occurrence of a character
# three or more times in a row
if re.search(r'(.)\1\1', v):
return "Weak Password: Same character repeats three or more times in a row"
# checks for occurrence of same string
# pattern( minimum of two character length)
# repeating
if re.search(r'(..)(.*?)\1', v):
return "Weak password: Same string pattern repetition"
else:
return "Strong Password!"
else:
return "Password length must be 9-20 characters!"
# Main method
def main():
# Driver code
print(password("Qggf!@ghf3"))
print(password("Gggksforgeeks"))
print(password("aaabnil1gu"))
print(password("Aasd!feasn"))
print(password("772*hd897"))
print(password(" "))
# Driver Code
if __name__ == '__main__':
main()
输出:
强密码！ 弱密码:相同字符串模式重复 弱密码:同一字符连续重复三次以上 强密码！ 强密码！ 密码不能是换行符或空格！
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