Python IMDbPY–获取系列每一季的每集年份
原文:https://www . geeksforgeeks . org/python-imdbpy-get-每季每集-年度最佳剧集/
在本文中，我们将看到如何从剧集信息集中获取该系列每一季每集的年份。每个系列都有季节，每个季节都有多集，即每集是季节的子集，季节是系列的子集。我们通过向剧集添加剧集信息集来获取剧集详细信息
为了做到这一点，我们必须做到以下几点–
1.借助 get_movie 方法 2 获取系列详情。使用 3 的更新方法为其添加剧集信息集。由于这个对象将作为字典，因此我们必须过滤对象 4。借助返回字典 5 的数据方法获取对象的主要数据。剧集的每一个键指的是季节，季节的每一个键指的是剧集 6。打印每集的年份
下面是实现
# importing the module
import imdb
# creating instance of IMDb
ia = imdb.IMDb()
# id
code = "6473300"
# getting information
series = ia.get_movie(code)
# adding new info set
ia.update(series, 'episodes')
# getting episodes of the series
episodes = series.data['episodes']
# printing the object i.e name
print(series)
print("=========")
# traversing each key
for i in episodes.keys():
# printing season number
print("Season" + str(i))
# traversing season i
for j in episodes[i]:
# getting year of episode
year = episodes[i][j]['year']
# printing title
print(" Ep " + str(j) + " year : " + str(year))
输出:
Mirzapur
=========
Season1
Ep 1 year : 2020
Ep 2 year : 2018
Ep 3 year : 2018
Ep 4 year : 2018
Ep 5 year : 2018
Ep 6 year : 2018
Ep 7 year : 2018
Ep 8 year : 2018
Ep 9 year : 2018
另一个例子
# importing the module
import imdb
# creating instance of IMDb
ia = imdb.IMDb()
# id
code = "6077448"
# getting information
series = ia.get_movie(code)
# adding new info set
ia.update(series, 'episodes')
# getting episodes of the series
episodes = series.data['episodes']
# printing the object i.e name
print(series)
print("=========")
# traversing each key
for i in episodes.keys():
# printing season number
print("Season" + str(i))
# traversing season i
for j in episodes[i]:
# getting year of episode
year = episodes[i][j]['year']
# printing title
print(" Ep " + str(j) + " year : " + str(year))
输出:
Sacred Games
=========
Season2
Ep 1 year : 2019
Ep 2 year : 2019
Ep 3 year : 2019
Ep 4 year : 2019
Ep 5 year : 2019
Ep 6 year : 2019
Ep 7 year : 2019
Ep 8 year : 2019
Season1
Ep 1 year : 2018
Ep 2 year : 2018
Ep 3 year : 2018
Ep 4 year : 2018
Ep 5 year : 2018
Ep 6 year : 2018
Ep 7 year : 2018
Ep 8 year : 2018
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