如果给定范围，Java 程序扩展字符串？
原文:https://www . geesforgeks . org/Java-program-expand-string-range-given/
假设我们给出了一个字符串，其中指定了一些范围，为了更好地理解，我们必须将给定范围之间的数字放在指定的位置，如下图所示。
插图:
Input : string x = "1-5, 8, 11-14, 18, 20, 26-29"
Output : string y = "1, 2, 3, 4, 5, 8, 11, 12,
13, 14, 18, 20, 26, 27, 28, 29"
进场:
为了解决上述问题，我们可以遵循以下方法:
- 首先，我们必须将字符串分割成字符串[]数组。我们必须在找到符号的地方分割字符串。
- 现在我们有一个包含元素的字符串[]数组。现在我们只去第一个索引最后一个元素，即 1，字符串[]数组的前一个索引第一个元素说它是 5。
- 之后，在 for 循环的帮助下，我们可以将 1 到 5 之间的数字相加，并将它们存储在 String 变量中。
- 上述过程一直持续到字符串数组的长度。
注:
在集合和各种实用方法的帮助下，我们可以很容易地解决这个问题，但是从性能角度来看，集合概念并不是一个好的选择。如果我们进行收集，性能会降低，时间复杂度也会增加。在下面的程序中，我们明确定义了自己的拆分方法和逻辑。
实施:
在这里，我们现在将在 clean java 程序的帮助下提出并讨论所有三个场景，如下所示:
例 1
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to Expand a String if Range is Given
// Main class
public class Solution {
// Main driver method
public static void expand(String word)
{
// Creating an object of StringBuffer class to
// make a modifiable string object
StringBuilder sb = new StringBuilder();
// Get all intervals
String[] strArr = word.split(", ");
// Traverse through every interval
for (int i = 0; i < strArr.length; i++) {
// Get lower and upper
String[] a = strArr[i].split("-");
// Setting high and low counters
if (a.length == 2) {
int low = Integer.parseInt(a[0]);
int high
= Integer.parseInt(a[a.length - 1]);
// Condition check holds true
// Till low counter is lesser or equal to
// high counter
while (low <= high) {
// Append all numbers
sb.append(low + " ");
low++;
}
}
// If we reaches here then
// High counter exceeds lower counter
else {
sb.append(strArr[i] + " ");
}
}
// Print the modifiable string
System.out.println(sb.toString());
}
// Method 2
// Main driver method
public static void main(String args[])
{
// Custom input string as input
String s = "1-5, 8, 11-14, 18, 20, 26-29";
expand(s);
}
}
Output:
1 2 3 4 5 8 11 12 13 14 18 20 26 27 28 29
例 2
Java 语言(一种计算机语言，尤用于创建网站)
// Java Program to Illustrate Expansion of String
// Main class
public class StringExpand {
// Method 1
// To split the string
static String[] split(String st)
{
// Count how many words in our string
// Irrespective of spaces
int wc = countWords(st);
String w[] = new String[wc];
char[] c = st.toCharArray();
int k = 0;
for (int i = 0; i < c.length; i++) {
// Initially declaring and initializing
// string as empty
String s = "";
// Whenever we found an non-space character
while (i < c.length && c[i] != ' ') {
// Concat with the String s
// Increment the value of i
s = s + c[i];
i++;
}
// If the String is not empty
if (s.length() != 0) {
// Add the String to the String[]
// array
w[k] = s;
k++;
}
}
// Returning the string array
return w;
}
// Method 2
// To count the number of words in a string
static int countWords(String str)
{
int count = 0;
for (int i = 0; i < str.length(); i++) {
// The below condition to check
// whether the first character is
// space or not
if (i == 0 && str.charAt(i) != ' '
|| str.charAt(i) != ' '
&& str.charAt(i - 1) == ' ') {
count++;
}
}
// Returning the count
return count;
}
// Method 3
// To expand the string
public static void expand(String s)
{
String p = s;
String[] arr = p.split("\\-");
String k = "";
// Traversing over array using for loop
for (int i = 0; i < arr.length; i++) {
// Case 1
if (i != arr.length - 1) {
String[] arr1 = arr[i].split(", ");
String[] arr2 = arr[i + 1].split(", ");
int a = Integer.parseInt(
arr1[arr1.length - 1]);
int b = Integer.parseInt(arr2[0]);
for (int j = a + 1; j < b; j++) {
arr[i] = arr[i] + ", " + j;
}
}
// Case 2
if (k != "")
k = k + ", " + arr[i];
// Case 3
else
k = k + arr[i];
}
// Print the expanded string
System.out.println(k);
}
// Method 4
// Main driver method
public static void main(String[] args)
{
// Custom string input
String s = "1-5, 8, 11-14, 18, 20, 26-29";
// Calling the method 3 to
// expand the string
expand(s);
}
}
Output:
1, 2, 3, 4, 5, 8, 11, 12, 13, 14, 18, 20, 26, 27, 28, 29
例 3
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to Expand a String if Range is Given
// Main class
// GenerateStringOnRange
class GFG {
// Method 1
// To generate string on range
public static String generateStringOn(String input)
{
String[] words = input.split(" ");
// Initially setting up range
String[] ranges = null;
int number = 0;
// Creating a StringBuffer object so that
// we can modify the string
StringBuffer buffer = new StringBuffer();
// Looking out for words by
// iterating using for each loop
for (String word : words) {
// To be replaced by
// using replace() method
word = word.replace(",", "");
// If word is containing "-" character
if (word.contains("-")) {
ranges = word.split("-");
number = Integer.parseInt(ranges[0]);
// Till number is within range
while (number
<= Integer.parseInt(ranges[1])) {
// Append , in between them
buffer.append(number + ", ");
number++;
}
}
// If we reaches here then
// word does contains "-"
else {
buffer.append(word + ", ");
}
}
// Return the StringBuffer object
return buffer.toString();
}
// Method 2
// Main driver method
public static void main(String[] args)
{
// Custom input string
String input = "1-5, 8, 11-14, 18, 20, 26-29";
// Calling the method 1 as created above
System.out.println(generateStringOn(input));
}
}
Output
1, 2, 3, 4, 5, 8, 11, 12, 13, 14, 18, 20, 26, 27, 28, 29,
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