十进制到十六进制转换的 Java 程序

原文:https://www . geesforgeks . org/Java-十进制到十六进制转换程序/

给定十进制数 N，将 N 转换为等效的十六进制数，即将基数为 10 的数转换为基数为 16 的数。十进制数字系统使用 10 位数字 0-9，十六进制数字系统使用 0-9，A-F 来表示任何数值。

例:

Input : 10
Output: A

Input : 2545
Output: 9F1

逼近:

  1. The number in the array is divided by 16 and the remainder is stored.
  2. Now divide the number by 16.
  3. Repeat the above two steps until the number is not equal to 0.
  4. Now print the array in reverse order.

实施:

示例

Java

// Java program to convert Decimal Number
// to Hexadecimal Number

// Importing input output classes
import java.io.*;

// Main class
public class GFG {

    // Method 1
    // To convert decimal to hexadecimal
    static void decTohex(int n)
    {
        // Creating an array to store octal number
        int[] hexNum = new int[100];

        // counter for hexadecimal number array
        int i = 0;
        while (n != 0) {

            // Storing remainder in hexadecimal array
            hexNum[i] = n % 16;
            n = n / 16;
            i++;
        }

        // Printing hexadecimal number array
        // in the reverse order
        for (int j = i - 1; j >= 0; j--) {
            if (hexNum[j] > 9)
                System.out.print((char)(55 + hexNum[j]));
            else
                System.out.print(hexNum[j]);
        }
    }

    // Method 2
    // Main driver method
    public static void main(String[] args)
    {
        // Custom input decimal number
        // to be converted into hexadecimal number
        int n = 2545;

        // Calling the above Method1 over number 'n'
        // to convert this decimal into hexadecimal number
        decTohex(n);
    }
}

输出

9F1

时间复杂度: O(对数 N)

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