LINQ |如何求给定序列的最小值？
在 LINQ，你可以使用 Min()函数找到给定序列的最小元素。此方法提供给定值集中的最小元素。它不支持 C# 中的查询语法，但在 VB.NET 支持。它在 C# 的可枚举和可查询类中都可用。如果集合中存在的所有元素都为 null，则返回 null。它返回任何类型的数据类型，这意味着您也可以将 Min 用于自定义类型的集合(不包含数值)，但为此，您必须实现 IComparable 接口。它可以处理可空、不可空的十进制、双精度、浮点、int 等。价值观。
例 1:
// C# program to find minimum
// value from the given array
using System;
using System.Linq;
class GFG {
// Main Method
static public void Main()
{
// Data source
int[] sequence = {20, 45, 50, 79, 90,
79, 89, 100, 567, 29};
// Display the sequence
Console.WriteLine("The sequence is: ");
foreach(int s in sequence)
{
Console.WriteLine(s);
}
// Finding the minimum element
// from the given sequence
// Using Min function
int result = sequence.Min();
Console.WriteLine("Minimum Value: {0}", result);
}
}
Output:
The sequence is:
20
45
50
79
90
79
89
100
567
29
Minimum Value: 20
例 2:
// C# program to find the Minimum
// salary of the employee
using System;
using System.Linq;
using System.Collections.Generic;
// Employee details
class Employee {
public int emp_id
{
get;
set;
}
public string emp_name
{
get;
set;
}
public string emp_gender
{
get;
set;
}
public string emp_hire_date
{
get;
set;
}
public int emp_salary
{
get;
set;
}
}
class GFG {
// Main method
static public void Main()
{
List<Employee> emp = new List<Employee>() {
new Employee() { emp_id = 209, emp_name = "Anjita", emp_gender = "Female", emp_hire_date = "12/3/2017", emp_salary = 20000 },
new Employee() { emp_id = 210, emp_name = "Soniya", emp_gender = "Female", emp_hire_date = "22/4/2018", emp_salary = 30000 },
new Employee() { emp_id = 211, emp_name = "Rohit", emp_gender = "Male", emp_hire_date = "3/5/2016", emp_salary = 40000 },
new Employee() { emp_id = 212, emp_name = "Supriya", emp_gender = "Female", emp_hire_date = "4/8/2017", emp_salary = 40000 },
new Employee() { emp_id = 213, emp_name = "Anil", emp_gender = "Male", emp_hire_date = "12/1/2016", emp_salary = 40000 },
new Employee() { emp_id = 214, emp_name = "Anju", emp_gender = "Female", emp_hire_date = "17/6/2015", emp_salary = 50000 },
};
// Find the minimum salary
// of the employee
// Using Min () method
var res = emp.Min(a => a.emp_salary);
Console.WriteLine("Minimum salary of the employee: {0}", res);
}
}
Output:
Minimum salary of the employee: 20000
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