Java 中的抽象顺序列表 conatinsAll()方法，示例
原文:https://www . geeksforgeeks . org/abstractsequentialist-conatinsall-method-in-Java-with-example/
Java 抽象顺序列表的 containsAll() 方法用于检查两个集合是否包含相同的元素。它将一个集合作为参数，如果该集合的所有元素都存在于另一个集合中，则返回 True。
语法:
public boolean containsAll(Collection C)
参数:参数 C 为集合。此参数指的是需要在此集合中检查其元素出现的集合。
返回值:如果此集合包含其他集合的所有元素，则该方法返回真，否则返回假。
下面的程序说明了 abstractsequentialist . conatinsall()方法:
程序 1:
// Java code to illustrate
// AbstractSequentialList containsAll()
import java.util.*;
class AbstractSequentialListDemo {
public static void main(String args[])
{
// Creating an empty Collection
AbstractSequentialList<String>
abs = new LinkedList<String>();
// Use add() method to
// add elements in the collection
abs.add("Geeks");
abs.add("for");
abs.add("Geeks");
abs.add("10");
abs.add("20");
// prints the list
System.out.println("AbstractSequentialList 1: "
+ abs);
// Creating another empty Collection
AbstractSequentialList<String>
abs2 = new LinkedList<String>();
// Use add() method to
// add elements in the collection
abs2.add("Geeks");
abs2.add("for");
abs2.add("Geeks");
abs2.add("10");
abs2.add("20");
// prints the list
System.out.println("AbstractSequentialList 2: "
+ abs2);
// Check if the collection
// contains same elements
System.out.println("\nBoth the collections same: "
+ abs.containsAll(abs2));
}
}
Output:
AbstractSequentialList 1: [Geeks, for, Geeks, 10, 20]
AbstractSequentialList 2: [Geeks, for, Geeks, 10, 20]
Both the collections same: true
程序 2:
// Java code to illustrate boolean containsAll()
import java.util.*;
class AbstractSequentialListDemo {
public static void main(String args[])
{
// Creating an empty Collection
AbstractSequentialList<String>
abs = new LinkedList<String>();
// Use add() method to
// add elements in the collection
abs.add("Geeks");
abs.add("for");
abs.add("Geeks");
// prints the list
System.out.println("AbstractSequentialList 1: "
+ abs);
// Creating another empty Collection
AbstractSequentialList<String>
abs2 = new LinkedList<String>();
// Use add() method to
// add elements in the collection
abs2.add("10");
abs2.add("20");
// prints the list
System.out.println("AbstractSequentialList 2: "
+ abs2);
// Check if the collection
// contains same elements
System.out.println("\nAre both collections same: "
+ abs.containsAll(abs2));
}
}
Output:
AbstractSequentialList 1: [Geeks, for, Geeks]
AbstractSequentialList 2: [10, 20]
Are both collections same: false
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