Java 中的 CompoundName startsWith()方法，示例
原文:https://www . geesforgeks . org/compound name-starts with-method-in-Java-with-examples/
javax.naming.CompoundName 类的start with()方法用于检查作为参数传递的复合名称是否是该复合名称的前缀。如果复合名称对象以“X”结尾，则复合名称“X”是该复合名称的前缀。如果 X 为空或者不是复合名称对象，则返回 false。
语法:
public boolean startsWith(Name n)
参数:此方法接受 n ，这是可能为空的要检查的复合名称。
返回值:如果 n 是 CompoundName，并且是该复合名称的前缀，则该方法返回 true，否则返回 false。
以下程序说明了 CompoundName.startsWith()方法: 程序 1:
// Java program to demonstrate
// CompoundName.startsWith()
import java.util.Properties;
import javax.naming.CompoundName;
import javax.naming.InvalidNameException;
public class GFG {
public static void main(String[] args)
throws InvalidNameException
{
// need properties for CompoundName
Properties props = new Properties();
props.put("jndi.syntax.separator", ":");
props.put("jndi.syntax.direction",
"left_to_right");
// create compound name object
CompoundName CompoundName1
= new CompoundName(
"1:2:4:6", props);
CompoundName CompoundName2
= new CompoundName(
"2:4:6", props);
// apply startsWith()
boolean Flag
= CompoundName1
.startsWith(CompoundName2);
// print value
if (Flag)
System.out.println(
"CompoundName1 starts with "
+ " CompoundName2");
else
System.out.println(
"CompoundName1 not starts with "
+ " CompoundName2");
}
}
Output:
CompoundName1 not starts with CompoundName2
程序 2:
// Java program to demonstrate
// CompoundName.startsWith() method
import java.util.Properties;
import javax.naming.CompoundName;
import javax.naming.InvalidNameException;
public class GFG {
public static void main(String[] args)
throws InvalidNameException
{
// need properties for CompoundName
Properties props = new Properties();
props.put("jndi.syntax.separator", "/");
props.put("jndi.syntax.direction",
"left_to_right");
// create compound name object
CompoundName CompoundName1
= new CompoundName(
"c/e/d/v/a/b/z/y/x/f",
props);
CompoundName CompoundName2
= new CompoundName(
"c/e/d",
props);
// apply startsWith()
boolean Flag
= CompoundName1
.startsWith(CompoundName2);
// print value
if (Flag)
System.out.println(
"CompoundName1 starts with "
+ " CompoundName2");
else
System.out.println(
"CompoundName1 not starts with "
+ " CompoundName2");
}
}
Output:
CompoundName1 starts with CompoundName2
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