Java 中 nano(长)方法持续时间示例

原文:https://www . geesforgeks . org/duration-with nanoslong-method-in-Java-with-examples/

java.time 包中持续时间类的with nano(long)方法用于获取该持续时间的不可变副本，指定的 nano 秒数量作为参数传递。

语法:

public Duration withNanos(long amountOfNanos)

参数:该方法接受一个参数 amountOfNanos ，即纳米秒的量。

返回值:该方法返回作为参数传递的纳米秒的持续时间。

异常:如果纳秒无效，此方法抛出日期时间异常。

以下示例说明了 Duration.withNanos()方法:

例 1:

// Java code to illustrate withNanos() method

import java.time.Duration;

public class GFG {
    public static void main(String[] args)
    {

        // Get the amount of nano-seconds
        int amountOfNanos = 30000;

        // Duration using parse() method
        Duration duration
            = Duration.parse("P2DT3H4M");

        // Get the duration in nano-seconds
        // using withNanos() method
        System.out.println(duration
                               .withNanos(amountOfNanos));
    }
}

输出:

PT51H4M0.00003S

例 2:

// Java code to illustrate withNanos() method

import java.time.Duration;

public class GFG {
    public static void main(String[] args)
    {

        // Get the amount of nano-seconds
        int amountOfNanos = 100000;

        // Duration using ofHours() method
        Duration duration = Duration.ofHours(5);

        // Get the duration in nano-seconds
        // using withNanos() method
        System.out.println(duration
                               .withNanos(amountOfNanos));
    }
}

输出:

PT5H0.0001S

参考:https://docs . Oracle . com/javase/9/docs/API/Java/time/duration . html # with nanos-int-

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