打印矩阵边界元素的 Java 程序

原文:https://www . geesforgeks . org/Java-程序到打印-矩阵的边界元素/

给定一个大小为行×列的矩阵，打印矩阵的边界元素。边界元素是那些在所有四个方向上都没有被元素包围的元素，即第一行、第一列、最后一行和最后一列中的元素。

例:

Input :
         1 2 3
         4 5 6
         7 8 9
Output:  
        1 2 3
        4   6
        7 8 9

方式:

  1. Take the matrix as the input of N × M dimension users.
  2. Use the for loop to print the boundary elements of the matrix.

下面是问题陈述的实现:

Java 语言(一种计算机语言，尤用于创建网站)

// Java Program to Print Boundary
// Elements of the Matrix

import java.util.*;

public class GFG {

    public void Boundary_Elements(int mat[][])
    {
        // Printing Input Matrix;
        System.out.println("Input Matrix is : ");

        for (int i = 0; i < mat.length; i++) {
            for (int j = 0; j < mat[i].length; j++) {

                System.out.print(mat[i][j]);
            }

            System.out.println();
        }

        // Printing Boundary Values of Matrix
        System.out.println("Resultant Matrix is :");

        for (int i = 0; i < mat.length; i++) {
            for (int j = 0; j < mat[i].length; j++) {

                if (i == 0 || j == 0 || i == mat.length - 1
                    || j == mat[i].length - 1) {
                    System.out.print(mat[i][j]);
                }
                else {
                    // Printing Space if element
                    // is not at Boundary
                    System.out.print(" ");
                }
            }

            System.out.println();
        }
    }
    public static void main(String[] args)
    {
        // Input Matrix
        int mat[][] = new int[][] { { 1, 2, 3 },
                                    { 4, 5, 6 },
                                    { 7, 8, 9 } };

        GFG B_Values = new GFG();

        B_Values.Boundary_Elements(mat);
    }
}

Output

Input Matrix is : 
123
456
789
Resultant Matrix is :
123
4 6
789

时间复杂度: O(N × M)，其中 N 和 M 是矩阵的维数。

空间复杂度: O(N × M)。

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