Java 中的 StrictMath sqrt()方法
原文:https://www . geesforgeks . org/strict math-sqrt-method-in-Java/
java . lang . StrictMath . sqrt()是 Java 中 strict math 类的一种内置方法，用于获取指定双精度值的精确舍入正平方根。
语法:
public static double sqrt(*double num*)
参数:函数接受双类型的单参数数，其平方根由函数返回。
返回值:该方法返回数的正平方根。它还会产生一些特殊情况:
- 如果参数为 NaN 或小于零，则函数返回 NaN
- 当参数为正无穷大时，函数返回正无穷大。
- 如果参数为零，该函数将使用与参数相同的符号返回零
- 结果是最接近参数值的数学平方根的双精度值。
示例:
Input: num = 25
Output: 5.0
Input: -729
Output: NaN
下面的程序说明了 java.lang.StrictMath.sqrt()方法的使用:
程序 1:
// Java Program to illustrate
// java.lang.StrictMath.sqrt() function
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 289, num2 = -729;
double num3 = 0.0, num4 = 547.87;
// It returns the positive square root
double sqrt_Value = StrictMath.sqrt(num1);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num2);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num3);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num4);
System.out.println("square root = " + sqrt_Value);
}
}
Output:
square root = 17.0
square root = NaN
square root = 0.0
square root = 23.406622994357814
程序 2:
// Java Program to illustrate
// java.lang.StrictMath.sqrt() function
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double num1 = 1160, num2 = -97;
double num3 = -0.0, num4 = 144;
double num5 = -72.18;
// It returns the positive square root
double sqrt_Value = StrictMath.sqrt(num1);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num2);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num3);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num4);
System.out.println("square root = " + sqrt_Value);
sqrt_Value = StrictMath.sqrt(num5);
System.out.println("square root = " + sqrt_Value);
}
}
Output:
square root = 34.058772731852805
square root = NaN
square root = -0.0
square root = 12.0
square root = NaN
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