Java 中的 SortedSet retainAll()方法,带示例

原文:https://www . geesforgeks . org/sorted set-retain all-method-in-Java-with-examples/

接口的 retainAll() 方法用于从这个 SortedSet 中保留指定集合中包含的所有元素。

*语法:*

public boolean retainAll(Collection c)

*参数:*该方法将集合 c 作为一个包含要从该排序集中保留的元素的参数。

*返回值:*如果这个排序集由于调用而改变,这个方法返回

*异常:*如果该集合包含空元素,并且指定的集合不允许空元素(可选),或者指定的集合为空,则该方法抛出空指针异常

*注*:sorted Set中的 retainAll()方法继承了 Java 中的 Set 接口

以下是说明retainal()方法的例子。

*例 1:*

Java 语言(一种计算机语言,尤用于创建网站)

// Java program to demonstrate
// retainAll() method for Sorted set

import java.util.*;

public class GFG1 {
    public static void main(String[] args)
        throws Exception
    {

        try {

            // Creating object of Set
            SortedSet<Integer> arrset1
                = new TreeSet<Integer>();

            // Populating arrset1
            arrset1.add(1);
            arrset1.add(2);
            arrset1.add(3);
            arrset1.add(4);
            arrset1.add(5);

            // print arrset1
            System.out.println(
                "Set before "
                + "retainAll() operation : "
                + arrset1);

            // Creating another object of  Set
            SortedSet<Integer> arrset2
                = new TreeSet<Integer>();
            arrset2.add(1);
            arrset2.add(2);
            arrset2.add(3);

            // print arrset2
            System.out.println(
                "Collection Elements"
                + " to be retained : "
                + arrset2);

            // Removing elements from arrset
            // specified in arrset2
            // using retainAll() method
            arrset1.retainAll(arrset2);

            // print arrset1
            System.out.println(
                "Set after "
                + "retainAll() operation : "
                + arrset1);
        }

        catch (NullPointerException e) {
            System.out.println(e);
        }
    }
}

**Output: 

Set before retainAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be retained : [1, 2, 3]
Set after retainAll() operation : [1, 2, 3]
```** 

**** 2:** *零点异常***

## **Java 语言(一种计算机语言尤用于创建网站)**

```java
// Java program to demonstrate
// retainAll() method for Sorted set

import java.util.*;

public class GFG1 {
    public static void main(String[] args)
        throws Exception
    {
        try {

            // Creating object of SortedSet<Integer>
            SortedSet<Integer> arrset1
                = new TreeSet<Integer>();

            // Populating arrset1
            arrset1.add(1);
            arrset1.add(2);
            arrset1.add(3);
            arrset1.add(4);
            arrset1.add(5);

            // print arrset1
            System.out.println(
                "Set before "
                + "retainAll() operation : "
                + arrset1);

            // Creating another object of Set<Integer>
            SortedSet<Integer> arrset2 = null;

            // print arrset2
            System.out.println(
                "Collection Elements "
                + "to be retained : "
                + arrset2);

            System.out.println(
                "\nTrying to pass "
                + "null as a "
                + "specified element\n");

            // Removing elements from arrset
            // specified in arrset2
            // using retainAll() method
            arrset1.retainAll(arrset2);

            // print arrset1
            System.out.println(
                "Set after "
                + "retainAll() operation : "
                + arrset1);
        }

        catch (NullPointerException e) {
            System.out.println(e);
        }
    }
}

**Output: 

```java Set before retainAll() operation : [1, 2, 3, 4, 5] Collection Elements to be retained : null

Trying to pass null as a specified element

java.lang.NullPointerException ```**

*参考*:https://docs . Oracle . com/javase/7/docs/API/Java/util/set . html # retailnall(Java . util . collection)T4】