求给定积和差的 N 个整数
给定两个整数 N 和 D，找到一组 N 个整数，使得它们的乘积和之差等于 D。 示例:
Input : N = 2, D = 1
Output : 2 3
Explanation:
product = 2*3 = 6,
Sum = 2 + 3 = 5.
Hence, 6 - 5 = 1(D).
Input : N = 3, D = 5.
Output : 1 2 8
Explanation :
Product = 1*2*8 = 16
Sum = 1+2+8 = 11.
Hence, 16-11 = 5(D).
一个棘手的解决方案是保留差 D，选择 N 个数字作为 N-2 '1 '，一个' 2 '和一个剩余的数字作为' N+D '。 和= (N-2)(1) + 2 + (N+D) = 2N + D. 积= 12(N+D) = 2N+2D 差=(2 * N+2 * D)–(2 * N+D)= D .
C++
// CPP code to generate numbers
// with difference between
// product and sum is D
#include <iostream>
using namespace std;
// Function to implement calculation
void findNumbers(int n, int d)
{
for (int i = 0; i < n - 2; i++)
cout << "1" << " ";
cout << "2" << " ";
cout << n + d << endl;
}
// Driver code
int main()
{
int N = 3, D = 5;
findNumbers(N, D);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java code to generate numbers
// with difference between
// product and sum is D
import java.io.*;
class GFG {
// Function to implement calculation
static void findNumbers(int n, int d)
{
for (int i = 0; i < n - 2; i++)
System.out.print("1" + " ");
System.out.print("2" + " ");
System.out.println(n + d);
}
// Driver code
public static void main(String args[])
{
int N = 3, D = 5;
findNumbers(N, D);
}
}
/* This code is contributed by Nikita Tiwari.*/
Python 3
# Python3 code to generate numbers with
# difference between product and sum is D
# Function to implement calculation
def pattern(n, d) :
for i in range(0, n - 2) :
print("1", end=" ")
print("2", end=" ")
print(n + d)
# Driver code
N = 3
D = 5
pattern(N, D)
# This code is contributed by 'Akanshgupta'
C
// C# code to generate numbers
// with difference between
// product and sum is D
using System;
class GFG {
// Function to implement calculation
static void findNumbers(int n, int d)
{
for (int i = 0; i < n - 2; i++)
Console.Write("1" + " ");
Console.Write("2" + " ");
Console.Write(n + d);
}
// Driver code
public static void Main()
{
int N = 3, D = 5;
findNumbers(N, D);
}
}
/* This code is contributed by vt_m.*/
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP code to generate numbers
// with difference between
// product and sum is D
// Function to implement
// calculation
function findNumbers($n, $d)
{
for ($i = 0; $i < $n - 2; $i++)
echo "1" ," ";
echo "2" , " ";
echo $n + $d ,"\n";
}
// Driver Code
$N = 3;
$D = 5;
findNumbers($N, $D);
// This code is contributed by ajit
?>
java 描述语言
<script>
// JavaScript program to generate numbers
// with difference between
// product and sum is D
// Function to implement calculation
function findNumbers(n, d)
{
for (let i = 0; i < n - 2; i++)
document.write("1" + " ");
document.write("2" + " ");
document.write(n + d);
}
// Driver code
let N = 3, D = 5;
findNumbers(N, D);
</script>
输出:
1 2 8
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