求正方形中四个半圆相交形成的阴影区域面积
原文:https://www . geesforgeks . org/find-正方形中四个半圆相交形成的阴影区域面积/
给定正方形的边长 a ，任务是找到正方形中四个半圆相交形成的阴影区域的面积，如下图所示:
例:
输入: a = 10 输出: 57 输入: a = 19 输出: 205.77
方法:阴影区域的面积将为:
面积(半圆 1) +面积(半圆 2) +面积(半圆 3) +面积(半圆 4)–面积(平方)。 由于所有半圆的半径相同，因此，所有半圆的面积都相等。所以，上面的公式可以写成: 4*(半圆面积)–面积(平方)
半圆的面积为 (3.14 * r 2 ) / 2 ，其中 r 为半圆的半径，等于 a / 2 。 因此，阴影区域的面积= 4 (3.14 (a * a)/8)–a * a
以下是上述方法的实现:
C++
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
// Function to return the area
// of the shaded region
float findAreaShaded(float a)
{
// Area of the square
float sqArea = a * a;
// Area of the semicircle
float semiCircleArea = (3.14 * (a * a) / 8);
// There are 4 semicircles
// shadedArea = Area of 4 semicircles - Area of square
float ShadedArea = 4 * semiCircleArea - sqArea;
return ShadedArea;
}
// Driver code
int main()
{
float a = 10;
cout << findAreaShaded(a);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java implementation of the approach
class GFG {
// Function to return the area
// of the shaded region
static float findAreaShaded(float a)
{
// Area of the square
float sqArea = a * a;
// Area of the semicircle
float semiCircleArea = (float)(3.14 * (a * a) / 8);
// There are 4 semicircles
// shadedArea = Area of 4 semicircles - Area of square
float ShadedArea = 4 * semiCircleArea - sqArea;
return ShadedArea;
}
// Driver code
public static void main(String[] args)
{
float a = 10;
System.out.println(findAreaShaded(a));
}
}
Python 3
# Python3 implementation of the approach
# Function to return the area
# of the shaded region
def findAreaShaded(a):
# Area of the square
sqArea = a * a;
# Area of the semicircle
semiCircleArea = (3.14 * (a * a ) / 8)
# There are 4 semicircles
# shadedArea = Area of 4 semicircles - Area of square
ShadedArea = 4 * semiCircleArea - sqArea ;
return ShadedArea;
# Driver code
if __name__ == '__main__':
a = 10
print(findAreaShaded(a))
C
// C# implementation of the approach
using System;
class GFG
{
// Function to return the area
// of the shaded region
static float findAreaShaded(float a)
{
// Area of the square
float sqArea = a * a;
// Area of the semicircle
float semiCircleArea = (float)(3.14 * (a * a) / 8);
// There are 4 semicircles
// shadedArea = Area of 4 semicircles - Area of square
float ShadedArea = 4 * semiCircleArea - sqArea;
return ShadedArea;
}
// Driver code
public static void Main()
{
float a = 10;
Console.WriteLine(findAreaShaded(a));
}
}
// This code is contributed by mohit kumar 29
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP implementation of the approach
// Function to return the area
// of the shaded region
function findAreaShaded($a)
{
// Area of the square
$sqArea = $a * $a;
// Area of the semicircle
$semiCircleArea = (3.14 * ($a * $a) / 8);
// There are 4 semicircles
// shadedArea = Area of 4 semicircles -
// Area of square
$ShadedArea = 4 * $semiCircleArea - $sqArea;
return $ShadedArea;
}
// Driver code
$a = 10;
echo findAreaShaded($a);
// This code is contributed by Ryuga
?>
java 描述语言
<script>
// Javascript implementation of the approach
// Function to return the area
// of the shaded region
function findAreaShaded( a)
{
// Area of the square
let sqArea = a * a;
// Area of the semicircle
let semiCircleArea = (3.14 * (a * a) / 8);
// There are 4 semicircles
// shadedArea = Area of 4 semicircles - Area of square
let ShadedArea = 4 * semiCircleArea - sqArea;
return ShadedArea;
}
// driver code
let a = 10;
document.write(findAreaShaded(a));
</script>
Output:
57
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