求曲线上给定点的切线
给定一条曲线[y = x(A–x)],任务是找到该曲线上给定点(x,y)的切线,其中 A,x,y 为整数。 例:
Input: A = 2, x = 2, y = 0
Output: y = -2x - 4
Since y = x(2 - x)
y = 2x - x^2 differentiate it with respect to x
dy/dx = 2 - 2x put x = 2, y = 0 in this equation
dy/dx = 2 - 2* 2 = -2
equation => (Y - 0 ) = ((-2))*( Y - 2)
=> y = -2x -4
Input: A = 3, x = 4, y = 5
Output: Not possible
Point is not on that curve
进场:
- 首先找出给定点是否在那条曲线上。
- 如果点在那条曲线上,那么求导数
- 通过将 x,y 放入 dy/dx 计算切线的坡度。
- 通过将切线的梯度和给定点的坐标代入直线方程的梯度点形式来确定切线的方程,其中法向方程为 Y–Y =(dy/dx)*(X–X)。
以下是上述方法的实现:
C++
// C++ program for find Tangent
// on a curve at given point
#include <bits/stdc++.h>
using namespace std;
// function for find Tangent
void findTangent(int A, int x, int y)
{
// differentiate given equation
int dif = A - x * 2;
// check that point on the curve or not
if (y == (2 * x - x * x)) {
// if differentiate is negative
if (dif < 0)
cout << "y = "
<< dif << "x" << (x * dif) + (y);
else if (dif > 0)
// differentiate is positive
cout << "y = "
<< dif << "x+" << -x * dif + y;
// differentiate is zero
else
cout << "Not possible";
}
}
// Driver code
int main()
{
// declare variable
int A = 2, x = 2, y = 0;
// call function findTangent
findTangent(A, x, y);
return 0;
}
Java 语言(一种计算机语言,尤用于创建网站)
// Java program for find Tangent
// on a curve at given point
import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
// function for find Tangent
static void findTangent(int A, int x, int y)
{
// differentiate given equation
int dif = A - x * 2;
// check that point on the curve or not
if (y == (2 * x - x * x)) {
// if differentiate is negative
if (dif < 0)
System.out.println( "y = "
+ dif + "x" + (x * dif + y));
else if (dif > 0)
// differentiate is positive
System.out.println( "y = "
+ dif + "x+" + -x * dif + y);
// differentiate is zero
else
System.out.println("Not possible");
}
}
// Driver code
public static void main(String args[])
{
// declare variable
int A = 2, x = 2, y = 0;
// call function findTangent
findTangent(A, x, y);
}
}
Python 3
# Python3 program for find Tangent
# on a curve at given point
# function for find Tangent
def findTangent(A, x, y) :
# differentiate given equation
dif = A - x * 2
# check that point on the curve or not
if y == (2 * x - x * x) :
# if differentiate is negative
if dif < 0 :
print("y =",dif,"x",(x * dif) + (y))
# differentiate is positive
elif dif > 0 :
print("y =",dif,"x+",-x * dif + y)
# differentiate is zero
else :
print("Not Possible")
# Driver code
if __name__ == "__main__" :
# declare variable
A, x, y = 2, 2, 0
# call function findTangent
findTangent(A, x, y)
# This code is contributed by
# ANKITRAI1
C
// C# program for find Tangent
// on a curve at given point
using System;
class GFG
{
// function for find Tangent
static void findTangent(int A, int x, int y)
{
// differentiate given equation
int dif = A - x * 2;
// check that point on the curve or not
if (y == (2 * x - x * x)) {
// if differentiate is negative
if (dif < 0)
Console.Write( "y = "
+ dif + "x" + (x * dif + y)+"\n");
else if (dif > 0)
// differentiate is positive
Console.Write( "y = "
+ dif + "x+" + -x * dif + y+"\n");
// differentiate is zero
else
Console.Write("Not possible"+"\n");
}
}
// Driver code
public static void Main()
{
// declare variable
int A = 2, x = 2, y = 0;
// call function findTangent
findTangent(A, x, y);
}
}
服务器端编程语言(Professional Hypertext Preprocessor 的缩写)
<?php
// PHP program for find Tangent
// on a curve at given point
// function for find Tangent
function findTangent($A, $x, $y)
{
// differentiate given equation
$dif = $A - $x * 2;
// check that point on the
// curve or not
if ($y == (2 * $x - $x * $x))
{
// if differentiate is negative
if ($dif < 0)
echo "y = ", $dif , "x" ,
($x * $dif) + ($y);
else if ($dif > 0)
// differentiate is positive
echo "y = ",
$dif , "x+" , -$x * $dif + $y;
// differentiate is zero
else
echo "Not possible";
}
}
// Driver code
// declare variable
$A = 2;
$x = 2;
$y = 0;
// call function findTangent
findTangent($A, $x, $y);
// This code is contributed by Sachin
?>
java 描述语言
<script>
// javascript program for find Tangent
// on a curve at given point
// function for find Tangent
function findTangent( A, x, y)
{
// differentiate given equation
var dif = A - x * 2;
// check that point on the curve or not
if (y == (2 * x - x * x)) {
// if differentiate is negative
if (dif < 0)
document.write( "y = "
+ dif + "x" + (x * dif + y)+"\n");
else if (dif > 0)
// differentiate is positive
document.write( "y = "
+ dif + "x+" + -x * dif + y+"\n");
// differentiate is zero
else
document.write("Not possible"+"\n");
}
}
// Driver code
// declare variable
var A = 2, x = 2, y = 0;
// call function findTangent
findTangent(A, x, y);
// This code is contributed by bunnyram19.
</script>
输出:
y = -2x-4
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