求数列 1、4、15、72、420 的第 n 项……
原文:https://www . geesforgeks . org/find-n 系列术语-1-4-15-72-420/
给定一个数字 N。任务是编写一个程序来查找下面系列中的第 N 个项:
1、4、15、72、420……
示例:
Input: 3
Output: 15
For N = 3, we know that the factorial of 3 is 6
Nth term = 6*(3+2)/2
= 15
Input: 6
Output: 2880
For N = 6, we know that the factorial of 6 is 720
Nth term = 620*(6+2)/2
= 2880
想法是先求给定数 N 的阶乘,也就是 N!。现在,上述系列中的第 N 项将是:
第 N 项 = N!* (N + 2)/2
下面是上述方法的实现:
C++
// CPP program to find N-th term of the series:
// 1, 4, 15, 72, 420…
#include <iostream>
using namespace std;
// Function to find factorial of N
int factorial(int N)
{
int fact = 1;
for (int i = 1; i <= N; i++)
fact = fact * i;
// return factorial of N
return fact;
}
// calculate Nth term of series
int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Function
int main()
{
int N = 6;
cout << nthTerm(N);
return 0;
}
Java 语言(一种计算机语言,尤用于创建网站)
// Java program to find N-th
// term of the series:
// 1, 4, 15, 72, 420
import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
// Function to find factorial of N
static int factorial(int N)
{
int fact = 1;
for (int i = 1; i <= N; i++)
fact = fact * i;
// return factorial of N
return fact;
}
// calculate Nth term of series
static int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Code
public static void main(String args[])
{
int N = 6;
System.out.println(nthTerm(N));
}
}
// This code is contributed by Subhadeep
Python 3
# Python 3 program to find
# N-th term of the series:
# 1, 4, 15, 72, 420…
# Function for finding
# factorial of N
def factorial(N) :
fact = 1
for i in range(1, N + 1) :
fact = fact * i
# return factorial of N
return fact
# Function for calculating
# Nth term of series
def nthTerm(N) :
# return nth term
return (factorial(N) * (N + 2) // 2)
# Driver code
if __name__ == "__main__" :
N = 6
# Function Calling
print(nthTerm(N))
# This code is contributed
# by ANKITRAI1
C
// C# program to find N-th
// term of the series:
// 1, 4, 15, 72, 420
using System;
class GFG
{
// Function to find factorial of N
static int factorial(int N)
{
int fact = 1;
for (int i = 1; i <= N; i++)
fact = fact * i;
// return factorial of N
return fact;
}
// calculate Nth term of series
static int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Code
public static void Main()
{
int N = 6;
Console.Write(nthTerm(N));
}
}
// This code is contributed by ChitraNayal
服务器端编程语言(Professional Hypertext Preprocessor 的缩写)
<?php
// PHP program to find
// N-th term of the series:
// 1, 4, 15, 72, 420…
// Function for finding
// factorial of N
function factorial($N)
{
$fact = 1;
for($i = 1; $i <= $N; $i++)
$fact = $fact * $i;
// return factorial of N
return $fact;
}
// Function for calculating
// Nth term of series
function nthTerm($N)
{
// return nth term
return (factorial($N) *
($N + 2) / 2);
}
// Driver code
$N = 6;
// Function Calling
echo nthTerm($N);
// This code is contributed
// by mits
?>
java 描述语言
<script>
// JavaScript program to find N-th term of the series:
// 1, 4, 15, 72, 420…
// Function to find factorial of N
function factorial( N)
{
let fact = 1;
for (let i = 1; i <= N; i++)
fact = fact * i;
// return factorial of N
return fact;
}
// calculate Nth term of series
function nthTerm(N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver code
let N = 6;
document.write( nthTerm(N) );
// This code contributed by aashish1995
</script>
Output:
2880
另一种方法:(使用递归)
C++
// CPP program to find N-th term of the series:
// 1, 4, 15, 72, 420…
// Using recursion
#include <iostream>
using namespace std;
// Function to find factorial of N
// with recursion
int factorial(int N)
{
// base condition
if( N == 0 || N == 1 )
return 1;
// use recursion
return N * factorial( N - 1 );
}
// calculate Nth term of series
int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Function
int main()
{
int N = 6;
cout << nthTerm(N);
return 0;
}
Java 语言(一种计算机语言,尤用于创建网站)
// Java program to find N-th
// term of the series:
// 1, 4, 15, 72, 420
import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
// Function to find factorial of N
static int factorial(int N)
{
// base condition
if( N == 0 || N == 1 )
return 1;
// use recursion
return N * factorial( N - 1 );
}
// calculate Nth term of series
static int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Code
public static void main(String args[])
{
int N = 6;
System.out.println(nthTerm(N));
}
}
Python 3
# Python3 program to find
# N-th term of the series:
# 1, 4, 15, 72, 420…
# Using recursion
# Function to find factorial
# of N with recursion
def factorial(N):
# base condition
if N == 0 or N == 1:
return 1
# use recursion
return N * factorial(N - 1)
def nthTerm(N):
# calculate Nth term of series
return (factorial(N) * (N + 2) // 2)
# Driver code
N = 6
print(nthTerm(N))
# This code is contributed
# by Shrikant13
C
// C# program to find N-th
// term of the series:
// 1, 4, 15, 72, 420
using System;
class GFG
{
// Function to find factorial of N
static int factorial(int N)
{
// base condition
if( N == 0 || N == 1 )
return 1;
// use recursion
return N * factorial( N - 1 );
}
// calculate Nth term of series
static int nthTerm(int N)
{
return (factorial(N) * (N + 2) / 2);
}
// Driver Code
public static void Main()
{
int N = 6;
Console.Write(nthTerm(N));
}
}
// This code is contributed by ChitraNayal
服务器端编程语言(Professional Hypertext Preprocessor 的缩写)
<?php
// PHP program to find
// N-th term of the series:
// 1, 4, 15, 72, 420…
// Function to find factorial
// of N with recursion
function factorial($N)
{
// base condition
if($N == 0 or $N == 1)
return 1;
// use recursion
return $N * factorial($N - 1);
}
// calculate Nth term of series
function nthTerm($N)
{
return (factorial($N) *
($N + 2) / 2);
}
// Driver Code
$N = 6;
echo nthTerm($N);
// This code is contributed
// by Shashank
?>
java 描述语言
<script>
// Javascript program to find N-th
// term of the series:
// 1, 4, 15, 72, 420
// Function to find factorial of N
function factorial(N)
{
// Base condition
if (N == 0 || N == 1)
return 1;
// Use recursion
return N * factorial(N - 1);
}
// Calculate Nth term of series
function nthTerm(N)
{
return(factorial(N) * (N + 2) / 2);
}
// Driver Code
let N = 6;
document.write(nthTerm(N));
// This code is contributed by avanitrachhadiya2155
</script>
Output:
2880
时间复杂度 : O(N) 注意:上面的代码对大 N 值不起作用,要找到大 N 的值,对大数使用阶乘的概念。
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