Java 中 BigInteger add()方法,带示例
原文:https://www . geesforgeks . org/big integer-add-method-in-Java-with-examples/
T2大整数。add(BigInteger val) 用于计算两个 BigInteger 的算术和。这种方法用于寻找比 java 的最大数据类型 double 的范围大得多的大量范围的算术加法,而不损害结果的精度。此方法对调用此方法的当前大整数执行操作,并将大整数作为参数传递。
语法:
public BigInteger add(BigInteger val)
参数:该方法接受一个参数值,该值是要添加到该大整数中的值。
返回值:这个方法返回一个保存和(this + val)的 BigInteger。
下面的程序用来说明 BigInteger 的 add()方法。
例 1:
// Java program to demonstrate
// add() method of BigInteger
import java.math.BigInteger;
public class GFG {
public static void main(String[] args)
{
// BigInteger object to store result
BigInteger sum;
// For user input
// Use Scanner or BufferedReader
// Two objects of String created
// Holds the values to calculate the sum
String input1
= "5454564684456454684646454545";
String input2
= "4256456484464684864864864864";
// Convert the string input to BigInteger
BigInteger a
= new BigInteger(input1);
BigInteger b
= new BigInteger(input2);
// Using add() method
sum = a.add(b);
// Display the result in BigInteger
System.out.println("The sum of\n"
+ a + " \nand\n" + b + " "
+ "\nis\n" + sum + "\n");
}
}
输出:
545456464684456468464645454545 和 425645646484464684864864 之和为 9711021168921139549511313194
从上面的例子可以看出,即使在增加了大量的长度之后,数据仍然是完全精确的。
例 2:
// Java program to demonstrate
// add() method of BigInteger
import java.math.BigInteger;
public class GFG {
public static void main(String[] args)
{
// BigInteger object to store result
BigInteger sum;
// double variable
// To store result as double
double d;
// For user input
// Use Scanner or BufferedReader
// Two objects of String
// Holds the values to sum
// The number's length is of 400 digits
// Which is out of range of double
String input1 = "012345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4554324324362432"
+ "7674637264783264"
+ "7832678463726478"
+ "3264736274673864"
+ "7364732463546354"
+ "6354632564532645"
+ "6325463546536453"
+ "6546325463546534"
+ "6325465345326456"
+ "4635463263453264"
+ "654632498739473";
String input2 = "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345678901234567"
+ "8901234567890123"
+ "4567890123456789"
+ "0123456789012345"
+ "6789012345678901"
+ "2345873271893718"
+ "2974897146378481"
+ "7489127847281478"
+ "2174871248721847"
+ "8748327463756475"
+ "6745781641263981"
+ "2839721897438974"
+ "3286574365764576"
+ "2376914689217817"
+ "4362473624721647"
+ "61247612748612746";
// convert the string input to BigInteger
BigInteger a
= new BigInteger(input1);
BigInteger b
= new BigInteger(input2);
// Using add() method
sum = a.add(b);
// Display the result in BigInteger
System.out.println("The sum of\n"
+ a + " \nand\n" + b + " "
+ "\nis\n" + sum);
// Using double to hold the result
d = Double.parseDouble(sum.toString());
// Display the result in double
System.out.println("Using double, Sum is "
+ d);
}
}
输出:
之和 1234567890123456789 . 01234567901
从上面的输出可以清楚地看出,对较大的整数使用 double 不是一个好的选择。 参考:https://docs . Oracle . com/en/Java/javase/12/docs/API/Java . base/Java/math/big integer . html # add(Java . math . big integer)
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