Java 中的大整数 signum()方法

原文:https://www . geesforgeks . org/big integer-signum-method-in-Java/

先决条件: 【大整数基础知识】 Java . math . big integer . signum()方法帮助我们识别大整数是正还是零还是负。它根据以下条件返回以下值之一:

  • 当数字为负数时返回-1
  • 当数字为零时返回 0
  • 当数字为正数时返回+1

语法:

public int signum()

参数:该方法不取任何参数。 返回值:当-1、0 或 1 分别为负、零或正时，该方法返回它们作为该大整数的值。

示例:

Input: 2300 
Output: 1
Explanation: 2300 is positive number 
so the method returns 1

Input: -5482549 
Output: -1

下面的程序说明了 BigInteger 的 signum()方法。

Java 语言(一种计算机语言，尤用于创建网站)

// Program Demonstrate signum() method of BigInteger

import java.math.*;

public class GFG {

    public static void main(String[] args)
    {
        // Creating BigInteger object
        BigInteger biginteger = new BigInteger("2300");

        // Call signum() method on bigInteger
        // store the return value as int
        int sigvalue = biginteger.signum();

        // Depending upon sign value find sign of biginteger
        String sign = null;
        if (sigvalue == 0)
            sign = "zero";
        else if (sigvalue == 1)
            sign = "positive";
        else
            sign = "negative";

        // Defining result
        String result = "BigInteger " + biginteger + " is " +
        sign + " and Sing value is " + sigvalue;

        // Print result
        System.out.println(result);
    }
}

Output: 

BigInteger 2300 is positive and Sing value is 1

参考:T2【https://docs . Oracle . com/javase/7/docs/API/Java/math/biginteger . html # signum()T4】

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