Java 中的 ByteBuffer putFloat()方法，带示例
原文:https://www . geeksforgeeks . org/bytebuffer-put float-methods-in-Java-with-examples/
浮点值
java.nio.ByteBuffer 类的 putFloat(float value) 方法用于按照当前字节顺序将包含给定浮点值的四个字节写入当前位置的缓冲区，然后将该位置递增四。
语法:
public abstract ByteBuffer putFloat(float value)
参数:该方法取一个参数浮点值，即需要写入的浮点值。
返回值:这个方法返回这个 ByteBuffer，将写入的浮点值作为参数传递。
异常:此方法抛出以下异常:
- Bufferovflowexception- If the current position of this buffer is not less than its limit
- ReadonlyBufferenexception- If this buffer is read-only,
下面是举例说明 putFloat(浮点值)方法的例子:
例 1:
// Java program to demonstrate
// putFloat() method
import java.nio.*;
import java.util.*;
public class GFG {
public static void main(String[] args)
{
// Declaring the capacity of the ByteBuffer
int capacity = 12;
// Creating the ByteBuffer
try {
// creating object of ByteBuffer
// and allocating size capacity
ByteBuffer bb = ByteBuffer.allocate(capacity);
// putting the value in ByteBuffer
// using putFloat() method
bb.putFloat(23.4f)
.putFloat(234.5f)
.putFloat(34.56f)
.rewind();
// print the ByteBuffer
System.out.print("Original ByteBuffer: [ ");
for (int i = 1; i <= capacity / 4; i++)
System.out.print(bb.getFloat() + " ");
System.out.print("]");
}
catch (BufferOverflowException e) {
System.out.println("Exception throws : " + e);
}
catch (ReadOnlyBufferException e) {
System.out.println("Exception throws : " + e);
}
}
}
输出:
Original ByteBuffer: [ 23.4 234.5 34.56 ]
例 2: 演示 BufferOverflowException。
// Java program to demonstrate
// putFloat() method
import java.nio.*;
import java.util.*;
public class GFG {
public static void main(String[] args)
{
// Declaring the capacity of the ByteBuffer
int capacity = 12;
// Creating the ByteBuffer
try {
// creating object of ByteBuffer
// and allocating size capacity
ByteBuffer bb = ByteBuffer.allocate(capacity);
// putting the value in ByteBuffer
// using putFloat() method
bb.putFloat(23.4f)
.putFloat(234.5f)
.putFloat(34.56f)
.rewind();
// print the ByteBuffer
System.out.print("Original ByteBuffer: [ ");
for (int i = 1; i <= capacity / 4; i++)
System.out.print(bb.getFloat() + " ");
System.out.print("]");
// putting the value in ByteBuffer
// using putFloat() method
bb.putFloat(234.55f);
}
catch (BufferOverflowException e) {
System.out.println("\n\nbuffer's current "
+ "position is not smaller"
+ " than its limit");
System.out.println("Exception throws : " + e);
}
catch (ReadOnlyBufferException e) {
System.out.println("Exception throws : " + e);
}
}
}
输出:
Original ByteBuffer: [ 23.4 234.5 34.56 ]
buffer's current position is not smaller than its limit
Exception throws : java.nio.BufferOverflowException
示例 3: 演示 ReadOnlyBufferException。
// Java program to demonstrate
// putFloat() method
import java.nio.*;
import java.util.*;
public class GFG {
public static void main(String[] args)
{
// Declaring the capacity of the ByteBuffer
int capacity = 12;
// Creating the ByteBuffer
try {
// creating object of ByteBuffer
// and allocating size capacity
ByteBuffer bb = ByteBuffer.allocate(capacity);
// putting the value in ByteBuffer
// using putFloat() method
bb.putFloat(23.4f)
.putFloat(234.5f)
.putFloat(34.56f)
.rewind();
// print the ByteBuffer
System.out.print("Original ByteBuffer: [ ");
for (int i = 1; i <= capacity / 4; i++)
System.out.print(bb.getFloat() + " ");
System.out.print("]");
// Creating a read-only copy of ByteBuffer
// using asReadOnlyBuffer() method
ByteBuffer bb1 = bb.asReadOnlyBuffer();
System.out.println("\n\nTrying to put the float value"
+ " in read-only buffer");
// putting the value in readonly ByteBuffer
// using putFloat() method
bb1.putFloat(234.5f);
}
catch (BufferOverflowException e) {
System.out.println("Exception throws : " + e);
}
catch (ReadOnlyBufferException e) {
System.out.println("Exception throws : " + e);
}
}
}
输出:
Original ByteBuffer: [ 23.4 234.5 34.56 ]
Trying to put the float value in read-only buffer
Exception throws : java.nio.ReadOnlyBufferException
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