七龙珠号码

原文:https://www.geeksforgeeks.org/heptacontagon-number/

给定一个数字 N ，任务是找到NthT5七角数字。

一个七角数是一类图形数。它有一个 70 边的多边形，叫做七边形。第 N 个七点计数是 70 个点，所有其他的点都围绕着一个共同的角，形成一个图案。前几个七连字符数字是 1，70，207，412……

例:

输入: N = 2 输出: 70 说明: 第二个七连串数字是 70。 输入: N = 3 输出: 207

方法:第 N 个十七碳数由公式给出:

  • s 边多边形的第 n 项= \frac{((s-2)n^2 - (s-4)n)}{2}

  • 因此 70 边多边形的第 n 项是

Tn =\frac{((70-2)n^2 - (70-4)n)}{2} =\frac{(68n^2 - 66)}{2}

以下是上述方法的实现:

C++

// C++ program for above approach
#include <bits/stdc++.h>
using namespace std;

// Finding the nth heptacontagon number
int heptacontagonNum(int n)
{
    return (68 * n * n - 66 * n) / 2;
}

// Driver code
int main()
{
    int N = 3;

    cout << "3rd heptacontagon Number is = "
         << heptacontagonNum(N);

    return 0;
}

// This code is contributed by shivanisinghss2110

C

// C program for above approach
#include <stdio.h>
#include <stdlib.h>

// Finding the nth heptacontagon Number
int heptacontagonNum(int n)
{
    return (68 * n * n - 66 * n) / 2;
}

// Driver code
int main()
{
    int N = 3;
    printf("3rd heptacontagon Number is = %d",
           heptacontagonNum(N));

    return 0;
}

Java 语言(一种计算机语言，尤用于创建网站)

// Java program for the above approach
class GFG{

// Finding the nth heptacontagon number
static int heptacontagonNum(int n)
{
    return (68 * n * n - 66 * n) / 2;
}

// Driver Code
public static void main(String[] args)
{
    int N = 3;
    System.out.println("3rd heptacontagon Number is = " +
                                    heptacontagonNum(N));
}
}

// This code is contributed by rutvik_56

Python 3

# Python3 program for above approach

# Finding the nth heptacontagon Number
def heptacontagonNum(n):

    return (68 * n * n - 66 * n) // 2;

# Driver code
N = 3;
print("3rd heptacontagon Number is =",
                 heptacontagonNum(N));

# This code is contributed by Akanksha_Rai

C

// C# program for the above approach
using System;
class GFG{

// Finding the nth heptacontagon number
static int heptacontagonNum(int n)
{
    return (68 * n * n - 66 * n) / 2;
}

// Driver Code
public static void Main()
{
    int N = 3;
    Console.Write("3rd heptacontagon Number is = " +
                               heptacontagonNum(N));
}
}

// This code is contributed by Akanksha_Rai

java 描述语言

<script>

// JavaScript program for above approach

// Finding the nth heptacontagon number
function heptacontagonNum(n)
{
    return (68 * n * n - 66 * n) / 2;
}

// Driver code

var N = 3;   
document.write("3rd heptacontagon Number is = " + heptacontagonNum(N));

</script>

Output: 

3rd heptacontagon Number is = 207

时间复杂度: O(1)

辅助空间: O(1)

参考资料:https://en . Wikipedia . org/wiki/hetaconagon

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