六角体编号
给定一个数字 N ,任务是找到 N 第T5】个六角数。
六角数是一类图形数。它有一个 64 边的多边形,叫做六角四边形。第 N 个六角点的个数是 64 个点,所有其他点都被一个共同的角包围并形成一个图案。前几个六连字符数字是 1,64,189,376,625,936,…
例:
输入: N = 2 输出: 64 说明: 第二个六连字符数为 64。 输入: N = 3 输出: 189
方法:第 N 个六价数由公式给出:
-
s 边多边形的第 n 项=
-
因此 64 边多边形的第 n 项是
以下是上述方法的实现:
C++
// C++ implementation for above approach
#include <bits/stdc++.h>
using namespace std;
// Function to Find the
// Nth Hexacontatetragon Number
int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver Code
int main()
{
int n = 3;
cout << HexacontatetragonNum(n);
return 0;
}
Java 语言(一种计算机语言,尤用于创建网站)
// Java program to find N-th
// Hexacontatetragon number
class GFG{
// Function to find the nth
// Hexacontatetragon number
static int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver code
public static void main(String[] args)
{
int n = 3;
System.out.print(HexacontatetragonNum(n));
}
}
// This code is contributed by shubham
Python 3
# Python3 implementation for above approach
# Function to Find the
# Nth Hexacontatetragon Number
def HexacontatetragonNum(n):
return (62 * n * n - 60 * n) / 2;
# Driver Code
n = 3;
print(HexacontatetragonNum(n));
# This code is contributed by Code_Mech
C
// C# program to find N-th
// Hexacontatetragon number
using System;
class GFG{
// Function to find the nth
// Hexacontatetragon number
static int HexacontatetragonNum(int n)
{
return (62 * n * n - 60 * n) / 2;
}
// Driver code
public static void Main()
{
int n = 3;
Console.Write(HexacontatetragonNum(n));
}
}
// This code is contributed by Code_Mech
java 描述语言
<script>
// Javascript program to find N-th
// Hexacontatetragon number
// Function to find the nth
// Hexacontatetragon number
function HexacontatetragonNum( n) {
return (62 * n * n - 60 * n) / 2;
}
// Driver code
let n = 3;
document.write(HexacontatetragonNum(n));
// This code contributed by aashish1995
</script>
Output:
189
时间复杂度: O(1)
参考资料:https://en . Wikipedia . org/wiki/hexagon tetra
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