交换矩阵中第一行和最后一行的元素
原文： https://www.geeksforgeeks.org/interchange-elements-of-first-and-last-rows-in-matrix/
给定4 x 4矩阵，我们必须交换第一行和最后一行的元素，并显示结果矩阵。
示例：
Input : 3 4 5 0
2 6 1 2
2 7 1 2
2 1 1 2
Output : 2 1 1 2
2 6 1 2
2 7 1 2
3 4 5 0
Input : 9 7 5 1
2 3 4 1
5 6 6 5
1 2 3 1
Output : 1 2 3 1
2 3 4 1
5 6 6 5
9 7 5 1
该方法非常简单，我们可以简单地交换矩阵第一行和最后一行的元素，以获取所需的矩阵作为输出。
下面是该方法的实现：
C++
// C++ code to swap the element of first
// and last row and display the result
#include <iostream>
using namespace std;
#define n 4
void interchangeFirstLast(int m[][n])
{
int rows = n;
// swapping of element between first
// and last rows
for (int i = 0; i < n; i++)
{
int t = m[0][i];
m[0][i] = m[rows - 1][i];
m[rows - 1][i] = t;
}
}
// Driver function
int main()
{
// input in the array
int m[n][n] = { { 8, 9, 7, 6 },
{ 4, 7, 6, 5 },
{ 3, 2, 1, 8 },
{ 9, 9, 7, 7 } };
interchangeFirstLast(m);
// printing the interchanged matrix
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
cout << m[i][j] << " ";
cout << endl;
}
}
// This code is contributed by Anant Agarwal.
Java
// Java code to swap the element of first
// and last row and display the result
import java.io.*;
public class Interchange {
static void interchangeFirstLast(int m[][])
{
int rows = m.length;
// swapping of element between first
// and last rows
for (int i = 0; i < m[0].length; i++) {
int t = m[0][i];
m[0][i] = m[rows-1][i];
m[rows-1][i] = t;
}
}
// Driver code
public static void main(String args[]) throws IOException
{
// input in the array
int m[][] = { { 8, 9, 7, 6 },
{ 4, 7, 6, 5 },
{ 3, 2, 1, 8 },
{ 9, 9, 7, 7 } };
interchangeFirstLast(m);
// printing the interchanged matrix
for (int i = 0; i < m.length; i++) {
for (int j = 0; j < m[0].length; j++)
System.out.print(m[i][j] + " ");
System.out.println();
}
}
}
Python3
# Python code to swap the element
# of first and last row and display
# the result
def interchangeFirstLast(mat, n, m):
rows = n
# swapping of element between
# first and last rows
for i in range(n):
t = mat[0][i]
mat[0][i] = mat[rows-1][i]
mat[rows-1][i] = t
# Driver Program
mat = [[8, 9, 7, 6],
[4, 7, 6, 5],
[3, 2, 1, 8],
[9, 9, 7, 7]]
n = 4
m = 4
interchangeFirstLast(mat, n, m)
# printing the interchanged matrix
for i in range(n):
for j in range(m):
print(mat[i][j], end = " ")
print("\n")
# This code is contributed by Shrikant13.
C
// C# code to swap the element of first
// and last row and display the result
using System;
class GFG
{
public static void interchangeFirstLast(int[][] m)
{
int rows = m.Length;
// swapping of element between first
// and last rows
for (int i = 0; i < m[0].Length; i++)
{
int t = m[0][i];
m[0][i] = m[rows - 1][i];
m[rows - 1][i] = t;
}
}
// Driver code
public static void Main(string[] args)
{
// input in the array
int[][] m = new int[][]
{
new int[] {8, 9, 7, 6},
new int[] {4, 7, 6, 5},
new int[] {3, 2, 1, 8},
new int[] {9, 9, 7, 7}
};
interchangeFirstLast(m);
// printing the interchanged matrix
for (int i = 0; i < m.Length; i++)
{
for (int j = 0; j < m[0].Length; j++)
{
Console.Write(m[i][j] + " ");
}
Console.WriteLine();
}
}
}
// This code is contributed by Shrikant13
PHP
<?php
// PHP code to swap the element of first
// and last row and display the result
$n = 4;
function interchangeFirstLast(&$m)
{
global $n;
$rows = $n;
// swapping of element between first
// and last rows
for ($i = 0; $i < $n; $i++)
{
$t = $m[0][$i];
$m[0][$i] = $m[$rows - 1][$i];
$m[$rows - 1][$i] = $t;
}
}
// Driver function
// input in the array
$m = array(array(8, 9, 7, 6),
array(4, 7, 6, 5),
array( 3, 2, 1, 8),
array(9, 9, 7, 7));
interchangeFirstLast($m);
// printing the interchanged matrix
for ($i = 0; $i < $n; $i++)
{
for ($j = 0; $j < $n; $j++)
echo $m[$i][$j] . " ";
echo "\n";
}
?>
输出：
9 9 7 7
4 7 6 5
3 2 1 8
8 9 7 6
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