用于数组旋转的块交换算法的 Java 程序

原文:https://www . geesforgeks . org/Java-程序换块-交换-算法换阵列-旋转/

编写一个函数 rotate(ar[],d,n),将大小为 n 的 arr[]旋转 d 个元素。

Array

将上面的数组旋转 2 将构成数组

ArrayRotation1

算法:

Initialize A = arr[0..d-1] and B = arr[d..n-1]
1) Do following until size of A is equal to size of B

  a)  If A is shorter, divide B into Bl and Br such that Br is of same 
       length as A. Swap A and Br to change ABlBr into BrBlA. Now A
       is at its final place, so recur on pieces of B.  

   b)  If A is longer, divide A into Al and Ar such that Al is of same 
       length as B Swap Al and B to change AlArB into BArAl. Now B
       is at its final place, so recur on pieces of A.

2)  Finally when A and B are of equal size, block swap them.

递归实现:

Java 语言(一种计算机语言,尤用于创建网站)

import java.util.*;

class GFG 
{
    // Wrapper over the recursive function leftRotateRec()
    // It left rotates arr[] by d.
    public static void leftRotate(int arr[], int d, 
                                                int n)
    {
        leftRotateRec(arr, 0, d, n);
    }

    public static void leftRotateRec(int arr[], int i, 
                                  int d, int n)
    {
        /* Return If number of elements to be rotated 
        is zero or equal to array size */
        if(d == 0 || d == n) 
            return; 

        /*If number of elements to be rotated 
        is exactly half of array size */
        if(n - d == d) 
        { 
            swap(arr, i, n - d + i, d); 
            return; 
        } 

        /* If A is shorter*/    
        if(d < n - d) 
        { 
            swap(arr, i, n - d + i, d); 
            leftRotateRec(arr, i, d, n - d);     
        } 
        else /* If B is shorter*/    
        { 
            swap(arr, i, d, n - d); 
            leftRotateRec(arr, n - d + i, 2 * d - n, d); /*This is tricky*/
        } 
    }

/*UTILITY FUNCTIONS*/
/* function to print an array */
public static void printArray(int arr[], int size) 
{ 
    int i; 
    for(i = 0; i < size; i++) 
        System.out.print(arr[i] + " "); 
    System.out.println(); 
} 

/*This function swaps d elements 
starting at index fi with d elements
starting at index si */
public static void swap(int arr[], int fi,
                        int si, int d) 
{ 
    int i, temp; 
    for(i = 0; i < d; i++) 
    { 
        temp = arr[fi + i]; 
        arr[fi + i] = arr[si + i]; 
        arr[si + i] = temp; 
    } 
} 

// Driver Code
public static void main (String[] args) 
{
    int arr[] = {1, 2, 3, 4, 5, 6, 7}; 
    leftRotate(arr, 2, 7); 
    printArray(arr, 7);     
}
}

// This code is contributed by codeseeker

输出:

3 5 4 6 7 1 2

迭代实现: 这里是同样算法的迭代实现。这里使用了相同的实用函数 swap()。

Java 语言(一种计算机语言,尤用于创建网站)

//Java code for above implementation
static void leftRotate(int arr[], int d, int n) 
{ 
int i, j; 
if(d == 0 || d == n) 
    return; 
i = d; 
j = n - d; 
while (i != j) 
{ 
    if(i < j) /*A is shorter*/
    { 
    swap(arr, d-i, d+j-i, i); 
    j -= i; 
    } 
    else /*B is shorter*/
    { 
    swap(arr, d-i, d, j); 
    i -= j; 
    } 
    // printArray(arr, 7); 
} 
/*Finally, block swap A and B*/
swap(arr, d-i, d, i); 
} 

时间复杂度: O(n) 其他阵轮换法请看以下帖子: https://www.geeksforgeeks.org/array-rotation/ https://www . geeksforgeeks . org/程序换阵-轮换-续-反转-算法/

参考文献: 【http://www.cs.bell-labs.com/cm/cs/pearls/s02b.pdf】 如发现以上程序/算法有任何 bug 或想分享任何关于区块交换算法的补充信息,请写评论。

更多详情请参考数组旋转的块交换算法的完整文章!