删除给定位置链表节点的 Javascript 程序
原文:https://www . geesforgeks . org/JavaScript-删除链表程序-给定位置的节点/
给定一个单链表和一个位置，删除给定位置的链表节点。
例:
Input: position = 1, Linked List = 8->2->3->1->7
Output: Linked List = 8->3->1->7
Input: position = 0, Linked List = 8->2->3->1->7
Output: Linked List = 2->3->1->7
如果要删除的节点是根节点，只需将其删除。要删除中间节点，我们必须有一个指向要删除的节点之前的节点的指针。所以如果位置不为零，我们运行一个位置循环 1 次，得到一个指向前一个节点的指针。
以下是上述想法的实现。
Javascript
<script>
// A complete working javascript program to
// delete a node in a linked list at a
// given position
// head of list
var head;
/* Linked list Node */
class Node
{
constructor(val)
{
this.data = val;
this.next = null;
}
}
/* Inserts a new Node at front of the list. */
function push(new_data)
{
/*
* 1 & 2: Allocate the Node & Put in the data
*/
var new_node = new Node(new_data);
/* 3\. Make next of new Node as head */
new_node.next = head;
/* 4\. Move the head to povar to new Node */
head = new_node;
}
/*
* Given a reference (pointer to pointer) to the
* head of a list and a position,
* deletes the node at the given position
*/
function deleteNode(position)
{
// If linked list is empty
if (head == null)
return;
// Store head node
var temp = head;
// If head needs to be removed
if (position == 0)
{
// Change head
head = temp.next;
return;
}
// Find previous node of the node to be deleted
for(i = 0; temp != null && i < position - 1; i++)
temp = temp.next;
// If position is more than number of nodes
if (temp == null || temp.next == null)
return;
// Node temp->next is the node to be deleted
// Store pointer to the next of node to be deleted
var next = temp.next.next;
// Unlink the deleted node from list
temp.next = next;
}
/*
* This function prints contents of linked
* list starting from the given node
*/
function printList()
{
var tnode = head;
while (tnode != null)
{
document.write(tnode.data + " ");
tnode = tnode.next;
}
}
/*
* Driver program to test above functions.
* Ideally this function should be in a
* separate user class. It is kept here
* to keep code compact
*/
/* Start with the empty list */
push(7);
push(1);
push(3);
push(2);
push(8);
document.write("Created Linked list is: <br/>");
printList();
// Delete node at position 4
deleteNode(4);
document.write("<br/>Linked List after " +
"Deletion at position 4: <br/>");
printList();
// This code is contributed by todaysgaurav
</script>
输出:
Created Linked List:
8 2 3 1 7
Linked List after Deletion at position 4:
8 2 3 1
详情请参考删除给定位置的链表节点整篇文章！
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