平截头体内最大的右圆柱体
给定平截头体高度
，顶半径
&底半径
。任务是找出最大的右圆柱体内可内接的体积。
示例:
Input : r = 5, R = 10, h = 4
Output : 314
Input : r = 7, R = 11, h = 6
Output : 923.16
进场 : 让:
- 气缸的高度= h1
- 圆柱体半径= r1
从图中可以清楚地看出:
- 圆柱体的高度=平截头体的高度
- 圆柱体半径= Rop-平截头体半径
所以，
h1 = h
r1 = r
以下是上述方法的实现:
C++
// C++ Program to find the biggest right circular cylinder
// that can be fit within a frustum
#include <bits/stdc++.h>
using namespace std;
// Function to find the biggest right circular cylinder
float cyl(float r, float R, float h)
{
// radii and height cannot be negative
if (h < 0 && r < 0 && R < 0)
return -1;
// radius of right circular cylinder
float r1 = r;
// height of right circular cylinder
float h1 = h;
// volume of right circular cylinder
float V = 3.14 * pow(r1, 2) * h1;
return V;
}
// Driver code
int main()
{
float r = 7, R = 11, h = 6;
cout << cyl(r, R, h) << endl;
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java Program to find the biggest right circular cylinder
// that can be fit within a frustum
import java.io.*;
class GFG {
// Function to find the biggest right circular cylinder
static float cyl(float r, float R, float h)
{
// radii and height cannot be negative
if (h < 0 && r < 0 && R < 0)
return -1;
// radius of right circular cylinder
float r1 = r;
// height of right circular cylinder
float h1 = h;
// volume of right circular cylinder
float V = (float)(3.14 * Math.pow(r1, 2) * h1);
return V;
}
// Driver code
public static void main (String[] args) {
float r = 7, R = 11, h = 6;
System.out.print( cyl(r, R, h));
}
}
// This code is contributed by anuj_67..
Python 3
# Python3 Program to find the biggest right circular cylinder
# that can be fit within a frustum
# Function to find the biggest right circular cylinder
def cyl(r, R, h) :
# radii and height cannot be negative
if (h < 0 and r < 0 and R < 0) :
return -1
# radius of right circular cylinder
r1 = r
# height of right circular cylinder
h1 = h
# volume of right circular cylinder
V = 3.14 * pow(r1, 2) * h1
return round(V,2)
# Driver code
if __name__ == "__main__" :
r, R, h = 7, 11, 6
print(cyl(r, R, h))
# This code is contributed by Ryuga
C
// C# Program to find the biggest right circular cylinder
// that can be fit within a frustum
using System;
class GFG {
// Function to find the biggest right circular cylinder
static float cyl(float r, float R, float h)
{
// radii and height cannot be negative
if (h < 0 && r < 0 && R < 0)
return -1;
// radius of right circular cylinder
float r1 = r;
// height of right circular cylinder
float h1 = h;
// volume of right circular cylinder
float V = (float)(3.14 * Math.Pow(r1, 2) * h1);
return V;
}
// Driver code
public static void Main () {
float r = 7, R = 11, h = 6;
Console.WriteLine( cyl(r, R, h));
}
}
// This code is contributed by anuj_67..
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP Program to find the biggest
// right circular cylinder that can
// be fit within a frustum
// Function to find the biggest
// right circular cylinder
function cyl($r, $R, $h)
{
// radii and height cannot be negative
if ($h < 0 && $r < 0 && $R < 0)
return -1;
// radius of right circular cylinder
$r1 = $r;
// height of right circular cylinder
$h1 = $h;
// volume of right circular cylinder
$V = (3.14 * pow($r1, 2) * $h1);
return $V;
}
// Driver code
$r = 7; $R = 11; $h = 6;
echo cyl($r, $R, $h);
// This code is contributed
// by Mukul Singh.
java 描述语言
<script>
// javascript Program to find the biggest right circular cylinder
// that can be fit within a frustum
// Function to find the biggest right circular cylinder
function cyl(r , R , h)
{
// radii and height cannot be negative
if (h < 0 && r < 0 && R < 0)
return -1;
// radius of right circular cylinder
var r1 = r;
// height of right circular cylinder
var h1 = h;
// volume of right circular cylinder
var V = (3.14 * Math.pow(r1, 2) * h1);
return V;
}
// Driver code
var r = 7, R = 11, h = 6;
document.write( cyl(r, R, h).toFixed(5));
// This code is contributed by Princi Singh
</script>
Output:
923.16
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