可被内接在正方体中的最大球体,而正方体又被内接在一个直角圆锥中
原文:https://www . geeksforgeeks . org/可在正方体中内接的最大球体-依次内接在直角圆锥内/
这里给定的是一个半径为 r 且垂直高度为 h 的右圆锥,它被内接在一个正方体中,正方体又被内接在一个球体中,任务是求球体的半径。 例:
Input: h = 5, r = 6
Output: 1.57306
Input: h = 8, r = 11
Output: 2.64156
接近 :
以下是上述方法的实现:
C++
// C++ Program to find the biggest sphere
// which is inscribed within a cube which in turn
// inscribed within a right circular cone
#include <bits/stdc++.h>
using namespace std;
// Function to find the radius of the sphere
float sphereSide(float h, float r)
{
// height and radius cannot be negative
if (h < 0 && r < 0)
return -1;
// radius of the sphere
float R = ((h * r * sqrt(2)) / (h + sqrt(2) * r)) / 2;
return R;
}
// Driver code
int main()
{
float h = 5, r = 6;
cout << sphereSide(h, r) << endl;
return 0;
}
Java 语言(一种计算机语言,尤用于创建网站)
// Java Program to find the biggest sphere
// which is inscribed within a cube which in turn
// inscribed within a right circular cone
import java.lang.Math;
class GFG
{
// Function to find the radius of the sphere
static float sphereSide(float h, float r)
{
// height and radius cannot be negative
if (h < 0 && r < 0)
return -1;
// radius of the sphere
float R = (float)((h * r * Math.sqrt(2)) /
(h + Math.sqrt(2) * r)) / 2;
return R;
}
// Driver code
public static void main(String[] args)
{
float h = 5, r = 6;
System.out.println(sphereSide(h, r));
}
}
// This code is contributed by Code_Mech.
Python 3
# Program to find the biggest sphere
# which is inscribed within a cube which in turn
# inscribed within a right circular cone
import math
# Function to find the radius of the sphere
def sphereSide(h, r):
# height and radius cannot be negative
if h < 0 and r < 0:
return -1
# radius of the sphere
R = (((h * r * math.sqrt(2))) /
(h + math.sqrt(2) * r) / 2)
return R
# Driver code
h = 5; r = 6
print(sphereSide(h, r))
# This code is contributed by Shrikant13
C
// C# Program to find the biggest sphere
// which is inscribed within a cube which in turn
// inscribed within a right circular cone
using System;
class GFG
{
// Function to find the radius of the sphere
static float sphereSide(float h, float r)
{
// height and radius cannot be negative
if (h < 0 && r < 0)
return -1;
// radius of the sphere
float R = (float)((h * r * Math.Sqrt(2)) /
(h + Math.Sqrt(2) * r)) / 2;
return R;
}
// Driver code
public static void Main()
{
float h = 5, r = 6;
Console.WriteLine(sphereSide(h, r));
}
}
// This code is contributed by Code_Mech
服务器端编程语言(Professional Hypertext Preprocessor 的缩写)
<?php
// PHP Program to find the biggest sphere
// which is inscribed within a cube which in turn
// inscribed within a right circular cone
// Function to find the radius of the sphere
function sphereSide($h, $r)
{
// height and radius cannot be negative
if ($h < 0 && $r < 0)
return -1;
// radius of the sphere
$R = (($h * $r * sqrt(2)) /
($h + sqrt(2) * $r)) / 2;
return $R;
}
// Driver code
$h = 5; $r = 6;
echo(sphereSide($h, $r));
// This code is contributed by Code_Mech.
?>
java 描述语言
<script>
// javascript Program to find the biggest sphere
// which is inscribed within a cube which in turn
// inscribed within a right circular cone
// Function to find the radius of the sphere
function sphereSide(h , r)
{
// height and radius cannot be negative
if (h < 0 && r < 0)
return -1;
// radius of the sphere
var R = ((h * r * Math.sqrt(2)) /
(h + Math.sqrt(2) * r)) / 2;
return R;
}
// Driver code
var h = 5, r = 6;
document.write(sphereSide(h, r).toFixed(5));
// This code is contributed by Amit Katiyar
</script>
Output:
1.57306
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