查找给定日期的本年日数
给定一个表示日期格式为 YYYY-MM-DD 的字符串 str ，任务是查找当前年份的日号。比如1ST1 月是一年中的 1 st 日，2ndT15】1 月是一年中的2ndT19】日，1STT23】2 月是一年中的32ndT27】日等等 例:**
输入: str = "2019-01-09" 输出: 9 输入: str = "2003-03-01" 输出: 60
进场:
- 从给定日期中提取年、月和日，并将其存储在变量年、月和日中。
- 创建一个数组days【】其中days【I】将存储 i th 月的天数。
- 更新计数=天[0] +天[1] + … +天[月–1]获得前几个月所有过去天数的计数。
- 如果给定的年份是闰年，则将该计数增加 1 ，以便计算 29 日2 月。
- 最后，将日加到当前月的日数上，打印出最终的日数。
以下是上述方法的实现:
C++
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
int days[] = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
// Function to return the day number
// of the year for the given date
int dayOfYear(string date)
{
// Extract the year, month and the
// day from the date string
int year = stoi(date.substr(0, 4));
int month = stoi(date.substr(5, 2));
int day = stoi(date.substr(8));
// If current year is a leap year and the date
// given is after the 28th of February then
// it must include the 29th February
if (month > 2 && year % 4 == 0
&& (year % 100 != 0 || year % 400 == 0)) {
++day;
}
// Add the days in the previous months
while (month-- > 0) {
day = day + days[month - 1];
}
return day;
}
// Driver code
int main()
{
string date = "2019-01-09";
cout << dayOfYear(date);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java implementation of the approach
class GFG
{
static int days [] = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
// Function to return the day number
// of the year for the given date
static int dayOfYear(String date)
{
// Extract the year, month and the
// day from the date string
int year = Integer.parseInt(date.substring(0, 4));
int month = Integer.parseInt(date.substring(5, 7));
int day = Integer.parseInt(date.substring(8));
// If current year is a leap year and the date
// given is after the 28th of February then
// it must include the 29th February
if (month > 2 && year % 4 == 0 &&
(year % 100 != 0 || year % 400 == 0))
{
++day;
}
// Add the days in the previous months
while (--month > 0)
{
day = day + days[month - 1];
}
return day;
}
// Driver code
public static void main (String[] args)
{
String date = "2019-01-09";
System.out.println(dayOfYear(date));
}
}
// This code is contributed by ihritik
Python 3
# Python3 implementation of the approach
days = [31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31];
# Function to return the day number
# of the year for the given date
def dayOfYear(date):
# Extract the year, month and the
# day from the date string
year = (int)(date[0:4]);
month = (int)(date[5:7]);
day = (int)(date[8:]);
# If current year is a leap year and the date
# given is after the 28th of February then
# it must include the 29th February
if (month > 2 and year % 4 == 0 and
(year % 100 != 0 or year % 400 == 0)):
day += 1;
# Add the days in the previous months
month -= 1;
while (month > 0):
day = day + days[month - 1];
month -= 1;
return day;
# Driver code
if __name__ == '__main__':
date = "2019-01-09";
print(dayOfYear(date));
# This code is contributed by Rajput-Ji
C
// C# implementation of the approach
using System;
class GFG
{
static int [] days = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };
// Function to return the day number
// of the year for the given date
static int dayOfYear(string date)
{
// Extract the year, month and the
// day from the date string
int year = Int32.Parse(date.Substring(0, 4));
int month = Int32.Parse(date.Substring(5, 2));
int day = Int32.Parse(date.Substring(8));
// If current year is a leap year and the date
// given is after the 28th of February then
// it must include the 29th February
if (month > 2 && year % 4 == 0 &&
(year % 100 != 0 || year % 400 == 0))
{
++day;
}
// Add the days in the previous months
while (--month > 0)
{
day = day + days[month - 1];
}
return day;
}
// Driver code
public static void Main ()
{
String date = "2019-01-09";
Console.WriteLine(dayOfYear(date));
}
}
// This code is contributed by ihritik
java 描述语言
<script>
// Javascript implementation of the approach
var days= [31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 ];
// Function to return the day number
// of the year for the given date
function dayOfYear( date)
{
// Extract the year, month and the
// day from the date string
var year = parseInt(date.substring(0, 4));
var month = parseInt(date.substring(5, 6));
var day = parseInt(date.substring(8));
// If current year is a leap year and the date
// given is after the 28th of February then
// it must include the 29th February
if (month > 2 && year % 4 == 0
&& (year % 100 != 0 || year % 400 == 0)) {
++day;
}
// Add the days in the previous months
while (month-- > 0) {
day = day + days[month - 1];
}
return day;
}
// Driver code
var date = "2019-01-09";
document.write( dayOfYear(date));
// This code is contributed by rutvik_56.
</script>
Output:
9
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