求数列 14，28，20，40 的第 n 项，…..
原文:https://www . geesforgeks . org/find-the-n-term-of-series-14-28-20-40/
给定一个数字
。任务是在以下系列中找到第 N 个术语:
14，28，20，40，32，64…..
例:
Input : N = 5
Output : 32
Input : N = 6
Output : 64
进场:
- 用 14 初始化第一个数字。
- 运行从 i = 2 到 N 的循环，并执行以下步骤:
- 对我来说，是上学期的两倍。例如，如果 i = 2，当前项将是 2 (I = 1 时的项)，即 214 = 28。
- 对于奇数 I，从上一项减去 8。
- 退出循环并打印最终数字。
以下是上述方法的实现:
C++
// CPP program to find the Nth term of
// the series 14, 28, 20, 40, …..
#include <iostream>
using namespace std;
// Function to find the N-th term
int findNth(int N)
{
// initializing the 1st number
int b = 14;
int i;
// loop from 2nd term to nth term
for (i = 2; i <= N; i++) {
// if i is even, double the
// previous number
if (i % 2 == 0)
b = b * 2;
// if i is odd, subtract 8 from
// previous number
else
b = b - 8;
}
return b;
}
// Driver Code
int main()
{
int N = 6;
cout << findNth(N);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to find the Nth term of
// the series 14, 28, 20, 40,
import java.io.*;
class GFG {
// Function to find the N-th term
static int findNth(int N)
{
// initializing the 1st number
int b = 14;
int i;
// loop from 2nd term to nth term
for (i = 2; i <= N; i++) {
// if i is even, double the
// previous number
if (i % 2 == 0)
b = b * 2;
// if i is odd, subtract 8 from
// previous number
else
b = b - 8;
}
return b;
}
// Driver Code
public static void main (String[] args) {
int N = 6;
System.out.print(findNth(N));
}
}
// This code is contributed by shs
Python 3
# Python 3 program to find the Nth term
# of the series 14, 28, 20, 40, …..
# Function to find the N-th term
def findNth(N):
# initializing the 1st number
b = 14
# loop from 2nd term to nth term
for i in range (2, N + 1):
# if i is even, double the
# previous number
if (i % 2 == 0):
b = b * 2
# if i is odd, subtract 8 from
# previous number
else:
b = b - 8
return b
# Driver Code
N = 6
print(findNth(N))
# This code is contributed
# by Akanksha Rai
C
// C# program to find the Nth term of
// the series 14, 28, 20, 40,
using System;
public class GFG{
// Function to find the N-th term
static int findNth(int N)
{
// initializing the 1st number
int b = 14;
int i;
// loop from 2nd term to nth term
for (i = 2; i <= N; i++) {
// if i is even, double the
// previous number
if (i % 2 == 0)
b = b * 2;
// if i is odd, subtract 8 from
// previous number
else
b = b - 8;
}
return b;
}
// Driver Code
static public void Main (){
int N = 6;
Console.WriteLine(findNth(N));
}
}
// This code is contributed by ajit
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to find the Nth term of
// the series 14, 28, 20, 40, …..
// Function to find the N-th term
function findNth($N)
{
// initializing the 1st number
$b = 14;
// loop from 2nd term to nth term
for ($i = 2; $i <= $N; $i++)
{
// if i is even, double the
// previous number
if ($i % 2 == 0)
$b = $b * 2;
// if i is odd, subtract 8 from
// previous number
else
$b = $b - 8;
}
return $b;
}
// Driver Code
$N = 6;
echo findNth($N);
// This code is contributed by akt_mit
?>
java 描述语言
<script>
// java script program to find the Nth term of
// the series 14, 28, 20, 40, …..
// Function to find the N-th term
function findNth(N)
{
// initializing the 1st number
let b = 14;
// loop from 2nd term to nth term
for (let i = 2; i <= N; i++)
{
// if i is even, double the
// previous number
if (i % 2 == 0)
b = b * 2;
// if i is odd, subtract 8 from
// previous number
else
b = b - 8;
}
return b;
}
// Driver Code
N = 6;
document.write(findNth(N));
// This code is contributed
// by pulamolu mohan pavan cse
</script>
Output:
64
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