求数列 2 + 6 + 13 + 23 +的第 n 项。。。
原文:https://www . geesforgeks . org/find-the-n-term-of-series-2-6-13-23/
给定一个整数 N 。任务是编写一个程序来找到给定系列的第 n 个术语:
2 + 6 + 13 + 23 + …
示例 :
Input : N = 5
Output : 36
Input : N = 10
Output : 146
参考如何找到级数的第 n 项一文，了解找到任意给定级数的第 n 项背后的想法。
给定系列的广义第 N 个术语为:
以下是上述方法的实施:
C++
//CPP program to find Nth term of the series
// 2 + 6 + 13 + 23 + 36 + ...
#include<bits/stdc++.h>
using namespace std;
// calculate Nth term of given series
int Nth_Term(int n)
{
return (3 * pow(n, 2) - n + 2) / (2);
}
// Driver code
int main()
{
int N = 5;
cout<<Nth_Term(N)<<endl;
}
Java 语言(一种计算机语言，尤用于创建网站)
//Java program to find Nth term of the series
// 2 + 6 + 13 + 23 + 36 + ...
import java.io.*;
class GFG {
// calculate Nth term of given series
static int Nth_Term(int n)
{
return (int)(3 * Math.pow(n, 2) - n + 2) / (2);
}
// Driver code
public static void main (String[] args) {
int N = 5;
System.out.println(Nth_Term(N));
}
}
// This code is contributed by anuj_67..
Python 3
# Python program to find Nth term of the series
# 2 + 6 + 13 + 23 + 36 + ...
# calculate Nth term of given series
def Nth_Term(n):
return (3 * pow(n, 2) - n + 2) // (2)
# Driver code
N = 5
print(Nth_Term(N))
C
// C# program to find Nth term of the series
// 2 + 6 + 13 + 23 + 36 + ...
class GFG
{
// calculate Nth term of given series
static int Nth_Term(int n)
{
return (int)(3 * System.Math.Pow(n, 2) -
n + 2) / (2);
}
// Driver code
static void Main ()
{
int N = 5;
System.Console.WriteLine(Nth_Term(N));
}
}
// This code is contributed by mits
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to find
// Nth term of the series
// 2 + 6 + 13 + 23 + 36 + ...
// calculate Nth term of given series
function Nth_Term($n)
{
return (3 * pow($n, 2) - $n + 2) / (2);
}
// Driver code
$N = 5;
echo (Nth_Term($N));
// This code is contributed
// by Sach_Code
?>
java 描述语言
<script>
// java script program to find
// Nth term of the series
// 2 + 6 + 13 + 23 + 36 + ...
// calculate Nth term of given series
function Nth_Term(n)
{
return (3 * Math.pow(n, 2) - n + 2) / (2);
}
// Driver code
let N = 5;
document.write (Nth_Term(N));
// This code is contributed
// by bobby
</script>
Output:
36
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