找出矩形区域的百分比变化
给定两个整数 P 和 Q ，表示矩形的长度和宽度的百分比变化，任务是在矩形的区域打印百分比变化。
示例:
输入: P = 10，Q = 20 输出: 32 说明: 让矩形的初始长度为 100，宽度为 80。 初始面积= 8000。 新长度= 110，新宽度= 96。因此，新面积= 10560。 面积变化百分比=((10560–8000)/8000)* 100 = 32。
输入: P = 20，Q =-10 T3】输出: 8 让矩形的初始长度为 100，宽度为 80。 初始面积= 8000。 新长度= 120，新宽度= 72。因此，新面积= 8640。 面积变化百分比=((8640–8000)/8000)* 100 = 8。
进场:
-
由于矩形的[面积由公式
``` area = length * breadth
```
给出](https://www.geeksforgeeks.org/program-area-perimeter-rectangle/) * 假设矩形的初始长度为 L ，矩形的宽度为 B 。因此，初始面积由 L * B 给出。 * 因此，新的长度和宽度给出为:
``` L' = L + ((P/100)L) B' = B + ((Q/100)B)
```
-
因此，新的长度和宽度给出为:
新增面积=[L+((C/100) L)][B+((D/100)* B)]
-
The percentage change in the area is given by the formula:
%变化=((新区-旧区)/旧区)*100
下面是上述方法的实现:
C++
``` // CPP implementation to find the percentage
include
using namespace std;
// change in the area when the percentage change // in the length and breadth is given
// Function to calculate percentage // change in area of rectangle int calculate_change(int length, int breadth){ int change = 0; change = length + breadth+((length * breadth)/100); return change; }
// Driver code int main() { int cL = 20; int cB = -10; int cA = calculate_change(cL, cB);
printf("%d",cA); return 0; } ```
Java 语言(一种计算机语言，尤用于创建网站)
``` // Java implementation to find the percentage import java.util.*;
class GFG{
// change in the area when the percentage change // in the length and breadth is given
// Function to calculate percentage // change in area of rectangle static int calculate_change(int length, int breadth){ int change = 0; change = length + breadth+((length * breadth)/100); return change; }
// Driver code public static void main(String args[]) { int cL = 20; int cB = -10; int cA = calculate_change(cL, cB);
System.out.println(+ cA);
} }
// This code is contributed by AbhiThakur
```
Python 3
```
Python3 implementation to find the percentage
change in the area when the percentage change
in the length and breadth is given
Function to calculate percentage
change in area of rectangle
def calculate_change(length, breadth): change = 0 change = length + breadth+((length * breadth)//100) return change
Driver code
if name == "main": cL = 20 cB = -10 cA = calculate_change(cL, cB)
print(cA)
This code is contributed by mohit kumar 29
```
C
``` // C# implementation to find the percentage using System; using System.Collections.Generic; using System.Linq;
class GFG {
// change in the area when the percentage change // in the length and breadth is given
// Function to calculate percentage // change in area of rectangle static int calculate_change(int length, int breadth){ int change = 0; change = length + breadth + ((length * breadth)/100); return change; }
// Driver Code public static void Main(String[] args) { int cL = 20; int cB = -10; int cA = calculate_change(cL, cB);
Console.Write(cA); } }
// This code is contributed by shivanisinghss2110 ```
Output:
``` 8
```
时间复杂度: O(1)
版权属于：月萌API www.moonapi.com，转载请注明出处
