求复数的实部和虚部
给定一个复数 Z ，任务是确定这个复数的实部和虚部。 例:
输入: z = 3 + 4i 输出:实部:3，虚部:4 输入:z = 6–8i 输出:实部:6，虚部:8
逼近:一个复数可以表示为 Z = x + yi ，其中 x 为实部， y 为虚部。 我们将按照以下步骤分离出实部和虚部
- 找出字符串中 + 或–运算符的索引
- 实部将是从索引 0 到长度(运算符的索引–1)的子串
- 虚部将是从索引(运算符+ 1 的索引)到(字符串长度–运算符的索引–2)的子字符串
执行:
C++
// C++ program to find the real and
// imaginary parts of a Complex Number
#include <bits/stdc++.h>
using namespace std;
// Function to find real and imaginary
// parts of a complex number
void findRealAndImag(string s)
{
// string length stored in variable l
int l = s.length();
// variable for the index of the separator
int i;
// Storing the index of '+'
if (s.find('+') < l) {
i = s.find('+');
}
// else storing the index of '-'
else {
i = s.find('-');
}
// Finding the real part
// of the complex number
string real = s.substr(0, i);
// Finding the imaginary part
// of the complex number
string imaginary = s.substr(i + 1, l - i - 2);
cout << "Real part: " << real << "\n";
cout << "Imaginary part: "
<< imaginary << "\n";
}
// Driver code
int main()
{
string s = "3+4i";
findRealAndImag(s);
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to find the real and
// imaginary parts of a Complex Number
class GFG
{
// Function to find real and imaginary
// parts of a complex number
static void findRealAndImag(String s)
{
// string length stored in variable l
int l = s.length();
// variable for the index of the separator
int i;
// Storing the index of '+'
if (s.indexOf('+') != -1) {
i = s.indexOf('+');
}
// else storing the index of '-'
else {
i = s.indexOf('-');
}
// Finding the real part
// of the complex number
String real = s.substring(0, i);
// Finding the imaginary part
// of the complex number
String imaginary = s.substring(i + 1, l - 1);
System.out.println("Real part: " + real );
System.out.println("Imaginary part: "+
imaginary);
}
// Driver code
public static void main(String []args)
{
String s = "3+4i";
findRealAndImag(s);
}
}
// This code is contributed by chitranayal
Python 3
# Python3 program to find the real and
# imaginary parts of a Complex Number
# Function to find real and imaginary
# parts of a complex number
def findRealAndImag(s) :
# string length stored in variable l
l = len(s)
# variable for the index of the separator
i = 0
# Storing the index of '+'
if (s.find('+') != -1):
i = s.find('+')
# else storing the index of '-'
else:
i = s.find('-');
# Finding the real part
# of the complex number
real = s[:i]
# Finding the imaginary part
# of the complex number
imaginary = s[i + 1:l - 1]
print("Real part:", real)
print("Imaginary part:", imaginary)
# Driver code
s = "3+4i";
findRealAndImag(s);
# This code is contributed by Sanjit_Prasad
C
// C# program to find the real and
// imaginary parts of a Complex Number
using System;
class GFG
{
// Function to find real and imaginary
// parts of a complex number
static void findRealAndImag(String s)
{
// string length stored in variable l
int l = s.Length;
// variable for the index of the separator
int i;
// Storing the index of '+'
if (s.IndexOf('+') != -1) {
i = s.IndexOf('+');
}
// else storing the index of '-'
else {
i = s.IndexOf('-');
}
// Finding the real part
// of the complex number
String real = s.Substring(0, i);
// Finding the imaginary part
// of the complex number
String imaginary = s.Substring(i + 1, l - i - 2);
Console.WriteLine("Real part: " + real );
Console.WriteLine("Imaginary part: "+
imaginary);
}
// Driver code
public static void Main(String []args)
{
String s = "3+4i";
findRealAndImag(s);
}
}
// This code is contributed by 29AjayKumar
java 描述语言
<script>
// JavaScript program to find the real and
// imaginary parts of a Complex Number
// Function to find real and imaginary
// parts of a complex number
function findRealAndImag(s)
{
// string length stored in variable l
let l = s.length - 1;
// variable for the index of the separator
let i;
// Storing the index of '+'
if (s.indexOf('+') != -1) {
i = s.indexOf('+');
}
// else storing the index of '-'
else {
i = s.indexOf('-');
}
// Finding the real part
// of the complex number
let real = s.substr(0, i);
// Finding the imaginary part
// of the complex number
let imaginary = s.substr(i + 1, l - 2 );
document.write("Real part: " + real +"<br/>" );
document.write("Imaginary part: "+
imaginary);
}
// Driver code
let s = "3+4i";
findRealAndImag(s);
</script>
Output:
Real part: 3
Imaginary part: 4
性能分析 s:
- 时间复杂度:在上面的方法中，由于不管字符串的长度如何，我们都在进行恒定数量的操作，因此时间复杂度为 O(1)
- 辅助空间复杂度:在上面的方法中，除了几个变量之外，我们没有使用任何额外的空间。所以辅助空间的复杂度是 O(1)
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