dsal 无向图中素数度的节点

无向图中素数度的节点

原文:https://www . geesforgeks . org/无向图中带素数度的节点/

给定一个具有 N 顶点和 M 边的无向图，任务是打印给定图的所有节点，其度数为素数。 示例:

输入: N = 4，arr[][] = { { 1，2 }，{ 1，3 }，{ 1，4 }，{ 2，3 }，{ 2，4 }，{ 3，4 } } 输出: 1 2 3 4 说明: 以下为上述信息的图表:

上图节点度为: 节点- >度 1->3 2->3 3->3 4->3 因此，素度节点为 1 2 3 4 输入: N = 5，arr[[]= { { 1，2 }，{ 1，3 }，{ 2，4 }，{ 2，5 } } 【T10

进场:

使用厄拉多塞筛计算 10 个 ^{5 个}以内的素数。
对于每个顶点，可以通过给定图在对应顶点的邻接表的长度来计算度数。
打印给定图中度数为质数的顶点。

以下是上述方法的实现:

C++

// C++ implementation of the approach

#include <bits/stdc++.h>
using namespace std;

int n = 10005;

// To store Prime Numbers
vector<bool> Prime(n + 1, true);

// Function to find the prime numbers
// till 10^5
void SieveOfEratosthenes()
{

    int i, j;
    Prime[0] = Prime[1] = false;
    for (i = 2; i * i <= 10005; i++) {

        // Traverse all multiple of i
        // and make it false
        if (Prime[i]) {

            for (j = 2 * i; j < 10005; j += i) {
                Prime[j] = false;
            }
        }
    }
}

// Function to print the nodes having
// prime degree
void primeDegreeNodes(int N, int M,
                      int edges[][2])
{
    // To store Adjacency List of
    // a Graph
    vector<int> Adj[N + 1];

    // Make Adjacency List
    for (int i = 0; i < M; i++) {
        int x = edges[i][0];
        int y = edges[i][1];

        Adj[x].push_back(y);
        Adj[y].push_back(x);
    }

    // To precompute prime numbers
    // till 10^5
    SieveOfEratosthenes();

    // Traverse each vertex
    for (int i = 1; i <= N; i++) {

        // Find size of Adjacency List
        int x = Adj[i].size();

        // If length of Adj[i] is Prime
        // then print it
        if (Prime[x])
            cout << i << ' ';
    }
}

// Driver code
int main()
{
    // Vertices and Edges
    int N = 4, M = 6;

    // Edges
    int edges[M][2] = { { 1, 2 }, { 1, 3 },
                        { 1, 4 }, { 2, 3 },
                        { 2, 4 }, { 3, 4 } };

    // Function Call
    primeDegreeNodes(N, M, edges);

    return 0;
}

Java 语言(一种计算机语言，尤用于创建网站)

// Java implementation of the approach
import java.util.*;
class GFG{

static int n = 10005;

// To store Prime Numbers
static boolean []Prime = new boolean[n + 1];

// Function to find the prime numbers
// till 10^5
static void SieveOfEratosthenes()
{
    int i, j;
    Prime[0] = Prime[1] = false;
    for (i = 2; i * i <= 10005; i++)
    {

        // Traverse all multiple of i
        // and make it false
        if (Prime[i])
        {
            for (j = 2 * i; j < 10005; j += i)
            {
                Prime[j] = false;
            }
        }
    }
}

// Function to print the nodes having
// prime degree
static void primeDegreeNodes(int N, int M,
                              int edges[][])
{
    // To store Adjacency List of
    // a Graph
    Vector<Integer> []Adj = new Vector[N + 1];
    for(int i = 0; i < Adj.length; i++)
        Adj[i] = new Vector<Integer>();

    // Make Adjacency List
    for (int i = 0; i < M; i++)
    {
        int x = edges[i][0];
        int y = edges[i][1];

        Adj[x].add(y);
        Adj[y].add(x);
    }

    // To precompute prime numbers
    // till 10^5
    SieveOfEratosthenes();

    // Traverse each vertex
    for (int i = 1; i <= N; i++)
    {

        // Find size of Adjacency List
        int x = Adj[i].size();

        // If length of Adj[i] is Prime
        // then print it
        if (Prime[x])
            System.out.print(i + " ");
    }
}

// Driver code
public static void main(String[] args)
{
    // Vertices and Edges
    int N = 4, M = 6;

    // Edges
    int edges[][] = { { 1, 2 }, { 1, 3 },
                      { 1, 4 }, { 2, 3 },
                      { 2, 4 }, { 3, 4 } };
    Arrays.fill(Prime, true);

    // Function Call
    primeDegreeNodes(N, M, edges);
}
}

// This code is contributed by sapnasingh4991

Python 3

# Python3 implementation of
# the above approach
n = 10005;

# To store Prime Numbers
Prime = [True for i in range(n + 1)]

# Function to find
# the prime numbers
# till 10^5
def SieveOfEratosthenes():

    i = 2   
    Prime[0] = Prime[1] = False;

    while i * i <= 10005:

        # Traverse all multiple
        # of i and make it false
        if (Prime[i]):           
            for j in range(2 * i, 10005):
                Prime[j] = False       
        i += 1  

# Function to print the
# nodes having prime degree
def primeDegreeNodes(N, M, edges):

    # To store Adjacency
    # List of a Graph
    Adj = [[] for i in range(N + 1)];

    # Make Adjacency List
    for i in range(M):
        x = edges[i][0];
        y = edges[i][1];

        Adj[x].append(y);
        Adj[y].append(x);   

    # To precompute prime
    # numbers till 10^5
    SieveOfEratosthenes();

    # Traverse each vertex
    for i in range(N + 1):

        # Find size of Adjacency List
        x = len(Adj[i]);

        # If length of Adj[i] is Prime
        # then print it
        if (Prime[x]):
            print(i, end = ' ')          

# Driver code
if __name__ == "__main__":

    # Vertices and Edges
    N = 4
    M = 6

    # Edges
    edges = [[1, 2], [1, 3],
             [1, 4], [2, 3],
             [2, 4], [3, 4]];

    # Function Call
    primeDegreeNodes(N, M, edges);

# This code is contributed by rutvik_56

C

// C# implementation of the approach
using System;
using System.Collections.Generic;

class GFG{

static int n = 10005;

// To store Prime Numbers
static bool []Prime = new bool[n + 1];

// Function to find the prime numbers
// till 10^5
static void SieveOfEratosthenes()
{
    int i, j;
    Prime[0] = Prime[1] = false;
    for(i = 2; i * i <= 10005; i++)
    {

       // Traverse all multiple of i
       // and make it false
       if (Prime[i])
       {
           for(j = 2 * i; j < 10005; j += i)
           {
              Prime[j] = false;
           }
       }
    }
}

// Function to print the nodes having
// prime degree
static void primeDegreeNodes(int N, int M,
                             int [,]edges)
{

    // To store Adjacency List of
    // a Graph
    List<int> []Adj = new List<int>[N + 1];
    for(int i = 0; i < Adj.Length; i++)
       Adj[i] = new List<int>();

    // Make Adjacency List
    for(int i = 0; i < M; i++)
    {
       int x = edges[i, 0];
       int y = edges[i, 1];

       Adj[x].Add(y);
       Adj[y].Add(x);
    }

    // To precompute prime numbers
    // till 10^5
    SieveOfEratosthenes();

    // Traverse each vertex
    for(int i = 1; i <= N; i++)
    {

       // Find size of Adjacency List
       int x = Adj[i].Count;

       // If length of Adj[i] is Prime
       // then print it
       if (Prime[x])
           Console.Write(i + " ");
    }
}

// Driver code
public static void Main(String[] args)
{

    // Vertices and Edges
    int N = 4, M = 6;

    // Edges
    int [,]edges = { { 1, 2 }, { 1, 3 },
                     { 1, 4 }, { 2, 3 },
                     { 2, 4 }, { 3, 4 } };

    for(int i = 0; i < Prime.Length; i++)
       Prime[i] = true;

    // Function Call
    primeDegreeNodes(N, M, edges);
}
}

// This code is contributed by 29AjayKumar

java 描述语言

<script>

// JavaScript implementation of the approach

let n = 10005;

// To store Prime Numbers
let Prime = new Array(n + 1).fill(true);

// Function to find the prime numbers
// till 10^5
function SieveOfEratosthenes()
{

    let i, j;
    Prime[0] = Prime[1] = false;
    for (i = 2; i * i <= 10005; i++) {

        // Traverse all multiple of i
        // and make it false
        if (Prime[i]) {

            for (j = 2 * i; j < 10005; j += i) {
                Prime[j] = false;
            }
        }
    }
}

// Function to print the nodes having
// prime degree
function primeDegreeNodes(N, M, edges)
{
    // To store Adjacency List of
    // a Graph
    let Adj = new Array();

    for(let i = 0; i < N + 1; i++){
        Adj.push(new Array())
    }

    // Make Adjacency List
    for (let i = 0; i < M; i++) {
        let x = edges[i][0];
        let y = edges[i][1];

        Adj[x].push(y);
        Adj[y].push(x);
    }

    // To precompute prime numbers
    // till 10^5
    SieveOfEratosthenes();

    // Traverse each vertex
    for (let i = 1; i <= N; i++) {

        // Find size of Adjacency List
        let x = Adj[i].length;

        // If length of Adj[i] is Prime
        // then print it
        if (Prime[x])
            document.write(i + ' ');
    }
}

// Driver code

// Vertices and Edges
let N = 4, M = 6;

    // Edges
let edges = [ [ 1, 2 ], [ 1, 3 ],
                [ 1, 4 ], [ 2, 3 ],
                [ 2, 4 ], [ 3, 4 ] ];

// Function Call
primeDegreeNodes(N, M, edges);

// This code is contributed by gfgking
</script>

Output:

1 2 3 4

时间复杂度: O(N + M) ，其中 N 为顶点数，M 为边数。

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无向图中素数度的节点

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《GeeksForGeeks 数据结构和算法中文教程 2022-11-03》

dsal 无向图中素数度的节点

无向图中素数度的节点

C++

Java 语言(一种计算机语言，尤用于创建网站)

Python 3

C

java 描述语言

留言

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