串联十进制字符串中的第 n 个字符
如果所有的十进制数都连接在一个字符串中，那么我们将得到一个看起来像字符串 P 的字符串，如下所示。我们需要告诉这个字符串的第 n 个字符。 P = " 12345678910111213141516171819202122232425262728293031…"
示例:
N = 10 10th character is 1
N = 11 11th character is 0
N = 50 50th character is 3
N = 190 190th character is 1
我们可以通过按长度断开字符串来解决这个问题。我们知道在十进制中，9 个数字的长度是 1，90 个数字的长度是 2，900 个数字的长度是 3，以此类推，所以我们可以根据给定的 N 跳过这些数字，就可以得到想要的字符。
Processing for N = 190 is explained below,
P[184..195] = “979899100101”
First getting length of number at N,
190 – 9 = 181 number length is more than 1
181 – 90*2 = 1 number length is more than 2
1 – 900*3 < 0 number length is 3
Now getting actual character at N,
1 character after maximum 2 length number(99) is, 1
Processing for N = 251 is explained below,
P[250..255] = “120121”
First getting length of number at N,
251 - 9 = 242 number length is more than 1
242 – 90*2 = 62 number length is more than 2
62 – 900*3 < 0 number length is 3
Now getting actual character at N,
62 characters after maximum 2 length number(99) is,
Ceil(62/3) = 21, 99 + 21 = 120
120 is the number at N, now getting actual digit,
62%3 = 2,
2nd digit of 120 is 2, so our answer will be 2 only.
请参见下面的代码，以便更好地理解，
C++
// C++ program to get Nth character in
// concatenated Decimal String
#include <bits/stdc++.h>
using namespace std;
// Utility method to get dth digit of number N
char getDigit(int N, int d)
{
string str;
stringstream ss;
ss << N;
ss >> str;
return str[d - 1];
}
// Method to return Nth character in concatenated
// decimal string
char getNthChar(int N)
{
// sum will store character escaped till now
int sum = 0, nine = 9;
// dist will store numbers escaped till now
int dist = 0, len;
// loop for number lengths
for (len = 1; ; len++)
{
// nine*len will be incremented characters
// and nine will be incremented numbers
sum += nine*len;
dist += nine;
if (sum >= N)
{
// restore variables to previous correct state
sum -= nine*len;
dist -= nine;
N -= sum;
break;
}
nine *= 10;
}
// get distance from last one digit less maximum
// number
int diff = ceil((double)N / len);
// d will store dth digit of current number
int d = N % len;
if (d == 0)
d = len;
// method will return dth numbered digit
// of (dist + diff) number
return getDigit(dist + diff, d);
}
// Driver code to test above methods
int main()
{
int N = 251;
cout << getNthChar(N) << endl;
return 0;
}
Java 语言(一种计算机语言，尤用于创建网站)
// Java program to get Nth character in
// concatenated Decimal String
class GFG
{
// Utility method to get dth digit of number N
static char getDigit(int N, int d)
{
String str=Integer.toString(N);
return str.charAt(d - 1);
}
// Method to return Nth character in concatenated
// decimal string
static char getNthChar(int N)
{
// sum will store character escaped till now
int sum = 0, nine = 9;
// dist will store numbers escaped till now
int dist = 0, len;
// loop for number lengths
for (len = 1; ; len++)
{
// nine*len will be incremented characters
// and nine will be incremented numbers
sum += nine * len;
dist += nine;
if (sum >= N)
{
// restore variables to previous correct state
sum -= nine * len;
dist -= nine;
N -= sum;
break;
}
nine *= 10;
}
// get distance from last one digit
// less maximum number
int diff = (int)(Math.ceil((double)(N) / (double)(len)));
// d will store dth digit of current number
int d = N % len;
if (d == 0)
d = len;
// method will return dth numbered digit
// of (dist + diff) number
return getDigit(dist + diff, d);
}
// Driver code
public static void main (String[] args)
{
int N = 251;
System.out.println(getNthChar(N));
}
}
// This code is contributed by mits
计算机编程语言
# Python program to get Nth character in
# concatenated Decimal String
# Method to get dth digit of number N
def getDigit(N, d):
string = str(N)
return string[d-1];
# Method to return Nth character in concatenated
# decimal string
def getNthChar(N):
# sum will store character escaped till now
sum = 0
nine = 9
# dist will store numbers escaped till now
dist = 0
# loop for number lengths
for len in range(1,N):
# nine*len will be incremented characters
# and nine will be incremented numbers
sum += nine*len
dist += nine
if (sum >= N):
# restore variables to previous correct state
sum -= nine*len
dist -= nine
N -= sum
break
nine *= 10
# get distance from last one digit less maximum
# number
diff = (N / len) + 1
# d will store dth digit of current number
d = N % len
if (d == 0):
d = len
# method will return dth numbered digit
# of (dist + diff) number
return getDigit(dist + diff, d);
# Driver code to test above methods
N = 251
print getNthChar(N)
# Contributed by Afzal_Saan
C
// C# program to get Nth character in
// concatenated Decimal String
using System;
class GFG
{
// Utility method to get dth digit of number N
static char getDigit(int N, int d)
{
string str = Convert.ToString(N);
return str[d - 1];
}
// Method to return Nth character in
// concatenated decimal string
static char getNthChar(int N)
{
// sum will store character
// escaped till now
int sum = 0, nine = 9;
// dist will store numbers
// escaped till now
int dist = 0, len;
// loop for number lengths
for (len = 1; ; len++)
{
// nine*len will be incremented characters
// and nine will be incremented numbers
sum += nine * len;
dist += nine;
if (sum >= N)
{
// restore variables to previous
// correct state
sum -= nine * len;
dist -= nine;
N -= sum;
break;
}
nine *= 10;
}
// get distance from last one digit
// less maximum number
int diff = (int)(Math.Ceiling((double)(N) /
(double)(len)));
// d will store dth digit of
// current number
int d = N % len;
if (d == 0)
d = len;
// method will return dth numbered
// digit of (dist + diff) number
return getDigit(dist + diff, d);
}
// Driver code
static void Main()
{
int N = 251;
Console.WriteLine(getNthChar(N));
}
}
// This code is contributed by mits
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
<?php
// PHP program to get Nth character
// in concatenated Decimal String
// Method to get dth digit
// of number N
function getDigit($N, $d)
{
$string = strval($N);
return $string[$d - 1];
}
// Method to return Nth character
// in concatenated decimal string
function getNthChar($N)
{
// sum will store character
// escaped till now
$sum = 0;
$nine = 9;
// dist will store numbers
// escaped till now
$dist = 0;
// loop for number lengths
for($len = 1; $len < $N; $len++)
{
// nine*len will be incremented characters
// and nine will be incremented numbers
$sum += $nine * $len;
$dist += $nine;
if ($sum >= $N)
{
// restore variables to
// previous correct state
$sum -= $nine * $len;
$dist -= $nine;
$N -= $sum;
break;
}
$nine *= 10;
}
// get distance from last one
// digit less maximum number
$diff = ($N / $len) + 1;
// d will store dth digit
// of current number
$d = $N % $len;
if ($d == 0)
$d = $len;
// method will return dth numbered
// digit of (dist + diff) number
return getDigit($dist + $diff, $d);
}
// Driver code
$N = 251;
echo getNthChar($N);
// This code is contributed by mits
?>
java 描述语言
<script>
// JavaScript program to get Nth
// character in concatenated
// Decimal String
// Utility method to get dth
// digit of number N
function getDigit(N, d)
{
let str = N.toString();
return str[d - 1];
}
// Method to return Nth character in
// concatenated decimal string
function getNthChar(N)
{
// Sum will store character
// escaped till now
let sum = 0, nine = 9;
// dist will store numbers
// escaped till now
let dist = 0, len;
// Loop for number lengths
for(len = 1; ; len++)
{
// nine*len will be incremented
// characters and nine will be
// incremented numbers
sum += nine * len;
dist += nine;
if (sum >= N)
{
// Restore variables to
// previous correct state
sum -= nine * len;
dist -= nine;
N -= sum;
break;
}
nine *= 10;
}
// Get distance from last one digit
// less maximum number
let diff = (Math.ceil((N) / (len)));
// d will store dth digit
// of current number
let d = N % len;
if (d == 0)
d = len;
// Method will return dth numbered digit
// of (dist + diff) number
return getDigit(dist + diff, d);
}
// Driver Code
let N = 251;
document.write(getNthChar(N));
// This code is contributed by code_hunt
</script>
输出:
2
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