连续变化的总百分比变化
给定一个代表百分比变化的数组 Arr。任务是确定这些百分比变化后的百分比增长。
示例:
Input: arr[] = {10, 20, 30, 10}
Output: Percentage change is = 88.76 %
Input: arr[] = {20, 15, 9, 7}
Output: Percentage change is = 60.94 %
无连续变化的解:-
让我们取一个数 N = 120。 并且百分比变化给出为，arr[] = {10，20，30，10} 现在，如果我们首先将 120 增加 10%，即 120 * 1.1，我们再次得到 N = 132 如果我们将其增加 20%，即 132 * 1.2，我们再次得到 N = 158.4 如果我们将其增加 30%，即 158.4 * 1.3，我们得到 N = 205.92 【T4
现在，百分比变化=(226.51–120)/120 = 0.8876 百分比变化= 0.8876 * 100 = 88.76 %
这个公式是如何工作的？ 设 x 为初始值。A%变化后，x 的值变为(x + xA/100) 连续 B%变化后，x 的值变为(x + xA/100) + (x + xA/100)B/100。所以 x 值的增量是 x(A + B + AB/100)/100。从百分比来看，我们可以说数值增加了(A+b+ A * B/100%)
进场:-
- 简单地说，在 arr[0]和 arr[1]之间应用连续的变化公式，并将结果存储在结果变量中
-
Now, calculate successive change between result and arr[2] using above formula and store the result in result variable and so on..
以下是上述方法的实现:
C++
``` // C++ implementation of above approach
include
using namespace std;
float successiveChange(int arr[], int N) { float var1, var2, result = 0;
var1 = arr[0]; var2 = arr[1];
// Calculate successive change of 1st 2 change result = var1 + var2 + (float(var1 * var2) / 100);
// Calculate successive change // for rest of the value for (int i = 2; i < N; i++) result = result + arr[i] + (float(result * arr[i]) / 100);
return result; }
// Driver code int main() { int arr[] = {10, 20, 30, 10}; int N = sizeof(arr) / sizeof(arr[0]);
// Calling function float result = successiveChange(arr, N);
cout << "Percentage change is = " << result << " %"; return 0; } ```
Java 语言(一种计算机语言，尤用于创建网站)
``` // Java implementation of above approach
import java.io.*;
class GFG {
static float successiveChange(int arr[], int N) { float var1, var2, result = 0;
var1 = arr[0]; var2 = arr[1];
// Calculate successive change of 1st 2 change result = var1 + var2 + ((var1 * var2) / 100);
// Calculate successive change // for rest of the value for (int i = 2; i < N; i++) result = result + arr[i] + ((result * arr[i]) / 100);
return result; }
// Driver code public static void main (String[] args) { int []arr = {10, 20, 30, 10}; int N = arr.length;
// Calling function float result = successiveChange(arr, N);
System.out.println("Percentage change is = " + result + " %"); } } // This code is contributed by shs.. ```
Python 3
```
Python implementation of above approach
def successiveChange(arr, N):
result = 0;
var1 = arr[0]; var2 = arr[1];
# Calculate successive change of 1st 2 change result = float(var1 + var2 + (float(var1 * var2) / 100));
# Calculate successive change # for rest of the value for i in range(2, N): result = (result + arr[i] + (float(result * arr[i]) / 100));
return result;
Driver code
arr = [10, 20, 30, 10]; N = len(arr) ;
Calling function
result = successiveChange(arr, N); print ("Percentage change is = %.2f" % (result), "%");
This code is contributed
by Shivi_Aggarwal
```
C
``` // C# implementation of above approach using System;
class GFG {
static float successiveChange(int []arr, int N) { float var1, var2, result = 0;
var1 = arr[0]; var2 = arr[1];
// Calculate successive change of 1st 2 change result = var1 + var2 + ((var1 * var2) / 100);
// Calculate successive change // for rest of the value for (int i = 2; i < N; i++) result = result + arr[i] + ((result * arr[i]) / 100);
return result; }
// Driver code public static void Main () { int []arr = {10, 20, 30, 10}; int N = arr.Length;
// Calling function float result = successiveChange(arr, N);
Console.WriteLine("Percentage change is = " + result + " %"); } } // This code is contributed by shs.. ```
服务器端编程语言（Professional Hypertext Preprocessor 的缩写）
``` <?php // PHP implementation of above approach
function successiveChange($arr, $N) { $result = 0;
$var1 = $arr[0]; $var2 = $arr[1];
// Calculate successive change // of 1st 2 change $result = $var1 + $var2 + (($var1 * $var2) / 100);
// Calculate successive change // for rest of the value for ($i = 2; $i <$N; $i++) $result = $result + $arr[$i] + (($result * $arr[$i]) / 100);
return $result; }
// Driver code $arr = array(10, 20, 30, 10); $N = count($arr);
// Calling function $result = successiveChange($arr, $N);
echo "Percentage change is = " , $result , " %";
// This code is contributed by shs.. ?> ```
Output:
``` Percentage change is = 88.76 %
```
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