在 NumPy 数组中查找唯一的行
原文:https://www . geesforgeks . org/find-unique-row-in-a-numpy-array/
在本文中，我们将讨论如何在 NumPy 数组中找到唯一的行。为了在 numpy 数组中找到唯一的行，我们使用了 NumPy 库的 numpy.unique() 函数。
语法: numpy.unique(ar，return_index=False，return_inverse=False，return_counts=False，axis=None)
现在，让我们看一个例子:
例 1:
Python 3
# import library
import numpy as np
# Create a 2D numpy array
arr2D = np.array([[11, 11, 12, 11],
[13, 11, 12, 11],
[16, 11, 12, 11],
[11, 11, 12, 11]])
print('Original Array :' ,
arr2D, sep = '\n')
# Get unique rows from
# complete 2D-array by
# passing axis = 0 in
# unique function along
# with 2D-array
uniqueRows = np.unique(arr2D,
axis = 0)
# print the output result
print('Unique Rows:',
uniqueRows, sep = '\n')
输出:
Original Array :
[[11 11 12 11]
[13 11 12 11]
[16 11 12 11]
[11 11 12 11]]
Unique Rows:
[[11 11 12 11]
[13 11 12 11]
[16 11 12 11]]
例 2:
Python 3
# import library
import numpy as np
# create 2d numpy array
array = np.array([[1, 2, 3, 4],
[3, 2, 4, 1],
[6, 8, 1, 2]])
print("Original array: \n",
array)
# Get unique rows from
# complete 2D-array by
# passing axis = 0 in
# unique function along
# with 2D-array
uniqueRows = np.unique(array,
axis = 0)
# print the output result
print('Unique Rows :',
uniqueRows,
sep = '\n')
输出:
Original array:
[[1 2 3 4]
[3 2 4 1]
[6 8 1 2]]
Unique Rows :
[[1 2 3 4]
[3 2 4 1]
[6 8 1 2]]
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