Python |统计列表中唯一的子列表
原文:https://www . geesforgeks . org/python-count-unique-sublist-in-list/
给定一个列表列表，任务是查找列表中唯一子列表的计数。
示例:
Input: [['Geek', 'for', 'geeks'], ['geeks', 'for'],
['for', 'Geeks', 'geek'], ['Geek', 'for', 'geeks']]
Output:
{('geeks', 'for'): 1, ('for', 'Geeks', 'geek'): 1,
('Geek', 'for', 'geeks'): 2}
下面是一些完成任务的方法。
方法#1:使用迭代
# Python code to count unique sublist within list
# Input list initialization
Input = [['Geek', 'for', 'geeks'], ['geeks', 'for'],
['for', 'Geeks', 'geek'], ['Geek', 'for', 'geeks']]
# Output list initialization
Output = {}
# Using Iteration
for lis in Input:
Output.setdefault(tuple(lis), list()).append(1)
for a, b in Output.items():
Output[a] = sum(b)
# Printing output
print(Output)
Output:
{(“极客”，“为”，“极客”):2，(“极客”，“为”):1，(“为”，“极客”，“极客”):1}
方法 2:使用计数器
# Python code to find count of unique list in list of list
# Importing counter from collection
from collections import Counter
# Input list initialization
lst = [[1, 2, 3], [4, 5, 6], [3, 2, 1], [1, 2, 3]]
# Using counter
Output = Counter([tuple(i) for i in lst])
# Printing output
print(Output)
Output:
Counter({(1, 2, 3): 2, (3, 2, 1): 1, (4, 5, 6): 1})
方法三:利用熊猫
# Python code to count unique sublist within list
# Importing
from collections import Counter
import pandas as pd
# Input list initialization
lst = [[1, 2, 3], [4, 5, 6], [3, 2, 1], [1, 2, 3]]
# Getting count
dict = Counter([tuple(i) for i in lst])
# Creating pandas dataframe
Output = pd.DataFrame(data ={'list': list(dict.keys()),
'count': list(dict.values())})
# Printing output
print(Output)
Output:
count list
0 1 (3, 2, 1)
1 1 (4, 5, 6)
2 2 (1, 2, 3)
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