Python–两个字典值列表的交叉映射
给定两个具有列表值的字典，通过检查值-键链接，执行第一个列表的键与其他列表的值的映射。
输入:test _ dict 1 = {“Gfg”:[4，10]，“Best”:[8，6]，“is”:[9，3]}，test_dict2 = {6 : [15，9]，8 : [6，3]，7 : [9，8]，9 : [10，11]} 输出:{“Best”:[6，3，15，9]，“is”:[10，11]} 解释:”
输入:test _ dict 1 = {“Gfg”:[4，10]，“Best”:[18，16]，“is”:[9，3]}，test_dict2 = {6 : [15，9]，8 : [6，3]，7 : [9，8]，9 : [10，11]} 输出 : {'is': [10，11]} 解释:只有 9 作为可能的键存在。
方法#1:使用循环+ setdefault() + extend()
上述功能的组合可以用来解决这个问题。在这种情况下，我们使用 get()执行获取具有值的匹配键的任务，并使用 setdefault 构造空列表进行映射。
Python 3
# Python3 code to demonstrate working of
# Cross mapping of Two dictionary value lists
# Using loop + setdefault() + extend()
# initializing dictionaries
test_dict1 = {"Gfg" : [4, 7], "Best" : [8, 6], "is" : [9, 3]}
test_dict2 = {6 : [15, 9], 8 : [6, 3], 7 : [9, 8], 9 : [10, 11]}
# printing original lists
print("The original dictionary 1 is : " + str(test_dict1))
print("The original dictionary 2 is : " + str(test_dict2))
res = {}
# getting all values of first dictionary
for key, val in test_dict1.items():
for key1 in val:
# getting result with default value list and extending
# according to value optained from get()
res.setdefault(key, []).extend(test_dict2.get(key1, []))
# printing result
print("The constructed dictionary : " + str(res))
Output
The original dictionary 1 is : {'Gfg': [4, 7], 'Best': [8, 6], 'is': [9, 3]}
The original dictionary 2 is : {6: [15, 9], 8: [6, 3], 7: [9, 8], 9: [10, 11]}
The constructed dictionary : {'Gfg': [9, 8], 'Best': [6, 3, 15, 9], 'is': [10, 11]}
方法二:使用列表理解+词典理解
这是解决这个问题的又一个方法。在这种情况下，我们使用列表理解提取所有映射，然后通过交叉映射提取的值来构建新的字典。
Python 3
# Python3 code to demonstrate working of
# Cross mapping of Two dictionary value lists
# Using list comprehension + dictionary comprehension
# initializing dictionaries
test_dict1 = {"Gfg" : [4, 7], "Best" : [8, 6], "is" : [9, 3]}
test_dict2 = {6 : [15, 9], 8 : [6, 3], 7 : [9, 8], 9 : [10, 11]}
# printing original lists
print("The original dictionary 1 is : " + str(test_dict1))
print("The original dictionary 2 is : " + str(test_dict2))
# using internal and external comprehension to
# solve problem
res = {key: [j for i in val if i in test_dict2 for j in test_dict2[i]]
for key, val in test_dict1.items()}
# printing result
print("The constructed dictionary : " + str(res))
Output
The original dictionary 1 is : {'Gfg': [4, 7], 'Best': [8, 6], 'is': [9, 3]}
The original dictionary 2 is : {6: [15, 9], 8: [6, 3], 7: [9, 8], 9: [10, 11]}
The constructed dictionary : {'Gfg': [9, 8], 'Best': [6, 3, 15, 9], 'is': [10, 11]}
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