Python–混合嵌套元组中的元素频率
原文:https://www . geesforgeks . org/python-elements-frequency-in-mixed-nested-tuple/
有时，在使用 Python 数据时，我们会遇到一个问题，即我们在单个元组中有嵌套和非嵌套形式的数据，我们希望计算它们中的元素频率。这种问题可能出现在网络开发和数据科学等领域。让我们讨论执行这项任务的某些方法。
输入 : test_tuple = (5，(6，(7，8，6))) 输出 : {5: 1，6: 2，7: 1，8: 1}
输入 : test_tuple = (5，6，7，8) 输出 : {5: 1，6: 1，7: 1，8: 1}
方法#1:使用递归+循环 这个问题的解决涉及两个步骤。首先，我们使用递归执行元组的展平，然后使用循环以强力方式执行计数。
# Python3 code to demonstrate working of
# Elements Frequency in Mixed Nested Tuple
# Using recursion + loop
# helper_fnc
def flatten(test_tuple):
for tup in test_tuple:
if isinstance(tup, tuple):
yield from flatten(tup)
else:
yield tup
# initializing tuple
test_tuple = (5, 6, (5, 6), 7, (8, 9), 9)
# printing original tuple
print("The original tuple : " + str(test_tuple))
# Elements Frequency in Mixed Nested Tuple
# Using recursion + loop
res = {}
for ele in flatten(test_tuple):
if ele not in res:
res[ele] = 0
res[ele] += 1
# printing result
print("The elements frequency : " + str(res))
Output :
The original tuple : (5, 6, (5, 6), 7, (8, 9), 9)
The elements frequency : {5: 2, 6: 2, 7: 1, 8: 1, 9: 2}
方法 2:使用Counter() +回复
这是解决这个问题的又一种方法。在本文中，我们使用 Counter()来执行对元素进行计数的任务。
# Python3 code to demonstrate working of
# Elements Frequency in Mixed Nested Tuple
# Using recursion + Counter()
from collections import Counter
# helper_fnc
def flatten(test_tuple):
for tup in test_tuple:
if isinstance(tup, tuple):
yield from flatten(tup)
else:
yield tup
# initializing tuple
test_tuple = (5, 6, (5, 6), 7, (8, 9), 9)
# printing original tuple
print("The original tuple : " + str(test_tuple))
# Elements Frequency in Mixed Nested Tuple
# Using recursion + Counter()
res = dict(Counter(flatten(test_tuple)))
# printing result
print("The elements frequency : " + str(res))
Output :
The original tuple : (5, 6, (5, 6), 7, (8, 9), 9)
The elements frequency : {5: 2, 6: 2, 7: 1, 8: 1, 9: 2}
版权属于：月萌API www.moonapi.com，转载请注明出处
