Python |使用 datetime.timedelta()方法的两个日期之间的差异(以分钟为单位)
原文:https://www . geesforgeks . org/python-分钟两个日期之间的差异-使用-datetime-timedelta-method/
要找出 Python 中两个日期之间的区别，可以使用日期时间库中的时间增量类。timedelta 类存储两个 datetime 对象之间的差异。 要以分钟的形式找到两个日期之间的差异，可以使用 timedelta 对象的属性秒，该属性可以进一步除以 60 转换为分钟。 例 1: 下面的程序取两个 datetime 对象，以分钟为单位找出它们之间的区别。
import datetime
# datetime(year, month, day, hour, minute, second)
a = datetime.datetime(2017, 6, 21, 18, 25, 30)
b = datetime.datetime(2017, 5, 16, 8, 21, 10)
# returns a timedelta object
c = a-b
print('Difference: ', c)
minutes = c.total_seconds() / 60
print('Total difference in minutes: ', minutes)
# returns the difference of the time of the day
minutes = c.seconds / 60
print('Difference in minutes: ', minutes)
输出:
Difference: 36 days, 10:04:20
Difference in minutes: 604.3333333333334
示例 2: 要获得更合适的答案，可以使用 divmod()返回以秒为单位的分钟小数部分:
import datetime
# datetime(year, month, day, hour, minute, second)
a = datetime.datetime(2017, 6, 21, 18, 25, 30)
b = datetime.datetime(2017, 5, 16, 8, 21, 10)
# returns a timedelta object
c = a-b
print('Difference: ', c)
# returns (minutes, seconds)
minutes = divmod(c.total_seconds(), 60)
print('Total difference in minutes: ', minutes[0], 'minutes',
minutes[1], 'seconds')
# returns the difference of the time of the day (minutes, seconds)
minutes = divmod(c.seconds, 60)
print('Total difference in minutes: ', minutes[0], 'minutes',
minutes[1], 'seconds')
输出:
Difference: 36 days, 10:04:20
Difference in minutes: 604 minutes 20 seconds
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