Python |累计嵌套元组列积
有时，在处理记录时，我们会遇到一个问题，即我们需要执行元组元素的索引式乘法。这可能会变得复杂，因为元组元素是元组，内部元素也是元组。让我们讨论一下解决这个问题的某些方法。 方法#1:使用 zip() +嵌套生成器表达式 以上功能的组合可以用来执行任务。在本文中，我们使用 zip()组合元组中的元素。迭代和产品逻辑由生成器表达式提供。
Python 3
# Python3 code to demonstrate working of
# Cumulative Nested Tuple Column Product
# using zip() + nested generator expression
# initialize tuples
test_tup1 = ((1, 3), (4, 5), (2, 9), (1, 10))
test_tup2 = ((6, 7), (3, 9), (1, 1), (7, 3))
# printing original tuples
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
# Cumulative Nested Tuple Column Product
# using zip() + nested generator expression
res = tuple(tuple(a * b for a, b in zip(tup1, tup2))\
for tup1, tup2 in zip(test_tup1, test_tup2))
# printing result
print("The resultant tuple after product : " + str(res))
Output :
The original tuple 1 : ((1, 3), (4, 5), (2, 9), (1, 10))
The original tuple 2 : ((6, 7), (3, 9), (1, 1), (7, 3))
The resultant tuple after product : ((6, 21), (12, 45), (2, 9), (7, 30))
方法 2:使用 isinstance() + zip() + loop +列表理解 以上功能的组合可以用来执行这个特定的任务。在这种情况下，我们检查嵌套类型并执行递归。这种方法可以提供 1 级以上嵌套的灵活性。
Python 3
# Python3 code to demonstrate working of
# Cumulative Nested Tuple Column Product
# using isinstance() + zip() + loop + list comprehension
# function to perform task
def tup_prod(tup1, tup2):
if isinstance(tup1, (list, tuple)) and isinstance(tup2, (list, tuple)):
return tuple(tup_prod(x, y) for x, y in zip(tup1, tup2))
return tup1 * tup2
# initialize tuples
test_tup1 = ((1, 3), (4, 5), (2, 9), (1, 10))
test_tup2 = ((6, 7), (3, 9), (1, 1), (7, 3))
# printing original tuples
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
# Cumulative Nested Tuple Column Product
# using isinstance() + zip() + loop + list comprehension
res = tuple(tup_prod(x, y) for x, y in zip(test_tup1, test_tup2))
# printing result
print("The resultant tuple after product : " + str(res))
Output :
The original tuple 1 : ((1, 3), (4, 5), (2, 9), (1, 10))
The original tuple 2 : ((6, 7), (3, 9), (1, 1), (7, 3))
The resultant tuple after product : ((6, 21), (12, 45), (2, 9), (7, 30))
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