Python–提取关键字的值,如果关键字出现在列表和字典中
原文:https://www . geesforgeks . org/python-extract-key-value-if-key-present-in-list-and-dictionary/
给定一个列表、字典和一个密钥 K,如果密钥同时存在于列表和字典中,则打印字典中的 K 值。
输入:test _ list =[“Gfg”,“is”,“Good”,“for”,“Geeks”],test _ dict = {“Gfg”:5,“Best”:6 },K =“Gfg” 输出 : 5 解释:“Gfg”存在于列表中,在字典中有值 5。
输入:test _ list =[“Good”、“for”、“Geeks”],test _ dict = {“Gfg”:5、“Best”:6 }、K =“Gfg” 输出:无 解释:“Gfg”不在 List 中。
方法#1:使用 all() +生成器表达式
上述功能的结合提供了解决这个问题的方法之一。在本文中,我们使用 all()来检查字典和列表中的出现。如果结果为真,则将值提取到结果中。
Python 3
# Python3 code to demonstrate working of
# Extract Key's Value, if Key Present in List and Dictionary
# Using all() + list comprehension
# initializing list
test_list = ["Gfg", "is", "Good", "for", "Geeks"]
# initializing Dictionary
test_dict = {"Gfg" : 2, "is" : 4, "Best" : 6}
# initializing K
K = "Gfg"
# printing original list and Dictionary
print("The original list : " + str(test_list))
print("The original Dictionary : " + str(test_dict))
# using all() to check for occurrence in list and dict
# encapsulating list and dictionary keys in list
res = None
if all(K in sub for sub in [test_dict, test_list]):
res = test_dict[K]
# printing result
print("Extracted Value : " + str(res))
Output
The original list : ['Gfg', 'is', 'Good', 'for', 'Geeks']
The original Dictionary : {'Gfg': 2, 'is': 4, 'Best': 6}
Extracted Value : 2
方法 2:使用 set() +交集()
这是检查两个容器中是否有钥匙的另一种方法。在本文中,我们计算列表和字典键的所有值的交集,并测试键在其中的出现。
Python 3
# Python3 code to demonstrate working of
# Extract Key's Value, if Key Present in List and Dictionary
# Using set() + intersection()
# initializing list
test_list = ["Gfg", "is", "Good", "for", "Geeks"]
# initializing Dictionary
test_dict = {"Gfg" : 2, "is" : 4, "Best" : 6}
# initializing K
K = "Gfg"
# printing original list and Dictionary
print("The original list : " + str(test_list))
print("The original Dictionary : " + str(test_dict))
# conversion of lists to set and intersection with keys
# using intersection
res = None
if K in set(test_list).intersection(test_dict):
res = test_dict[K]
# printing result
print("Extracted Value : " + str(res))
Output
The original list : ['Gfg', 'is', 'Good', 'for', 'Geeks']
The original Dictionary : {'Gfg': 2, 'is': 4, 'Best': 6}
Extracted Value : 2
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