Python–如果字符串长度等于 K，则过滤字符串元组
原文:https://www . geesforgeks . org/python-filter-string-元组-if-string-length-equals-k/
给定元组列表，过滤元组，其元素字符串长度等于 k
输入:test _ list =[(“ABC”、“Gfg”、“CS1”)、(“Gfg”、“Best”)、(“Gfg”、“WoOW”)]，K = 3 输出:[(“ABC”、“Gfg”、“CS1”)] :以上元组中所有字符串长度均为 3。
*输入*:test _ list =[(“ABCD”、“Gfg”、“CS1”)、(“Gfg”、“Best”)、(“Gfg”、“WoOW”)]，K = 3 输出 : [] 解释:以上元组中没有长度为 3 的字符串。
*方法#1:使用循环*
在这种情况下，我们运行嵌套循环来测试每个字符串，如果等于 K，那么元组被附加到结果列表，否则它被省略。
Python 3
# Python3 code to demonstrate working of
# Filter String Tuples if String lengths equals K
# Using loop
# initializing list
test_list = [("ABC", "Gfg", "CS1"), ("Gfg", "Best"), ("Gfg", "WoW")]
# printing original list
print("The original list is : " + str(test_list))
# initializing K
K = 3
res_list = []
for sub in test_list:
res = True
for ele in sub:
# check using len() the lengths
if len(ele) != K :
res = False
break
if res:
res_list.append(sub)
# printing result
print("The filtered tuples : " + str(res_list))
**Output
The original list is : [('ABC', 'Gfg', 'CS1'), ('Gfg', 'Best'), ('Gfg', 'WoW')]
The filtered tuples : [('ABC', 'Gfg', 'CS1'), ('Gfg', 'WoW')]
```**
****方法 2:使用 all() +列表理解****
**压缩方式，使用 all()检查长度等价性，并使用列表理解进行迭代。**
## **Python 3**
```py
# Python3 code to demonstrate working of
# Filter String Tuples if String lengths equals K
# Using all() + list comprehension
# initializing list
test_list = [("ABC", "Gfg", "CS1"), ("Gfg", "Best"), ("Gfg", "WoW")]
# printing original list
print("The original list is : " + str(test_list))
# initializing K
K = 3
# all checks for all lengths equals K
res = [sub for sub in test_list if all(len(ele) == K for ele in sub)]
# printing result
print("The filtered tuples : " + str(res))
**Output
```py The original list is : [('ABC', 'Gfg', 'CS1'), ('Gfg', 'Best'), ('Gfg', 'WoW')] The filtered tuples : [('ABC', 'Gfg', 'CS1'), ('Gfg', 'WoW')]
```**
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