Python–过滤无空格字符串的行
原文:https://www . geesforgeks . org/python-filter-row-不带空格-strings/
给定矩阵，提取字符串中没有空格的行。
示例:
输入:test _ list =[[“gfg 是”、“最好的”]、[“gfg”、“好的”]、[“gfg 很酷”]、[“爱”、“gfg”]] 输出:[‘gfg’，‘好的’]、[‘爱’，‘gfg’]] 解释:两个列表都有字符串没有空格。
输入:test _ List =[[“gfg 是”、“最好”]、[“gfg”、“好”]、[“gfg 是酷”]、[“爱”、“gfg”]] 输出:[“‘爱’、‘gfg’] 解释 : List 有字符串没有空格。
在这种情况下，我们使用正则表达式检查每个字符串中是否没有空格，使用 any()检查是否有空格，该行不会被添加。
Python 3
# Python3 code to demonstrate working of
# Filter rows without Space Strings
# Using list comprehension + any() + regex
import re
# initializing list
test_list = [["gfg is", "best"], ["gfg", "good"],
["gfg is cool"], ["love", "gfg"]]
# printing original list
print("The original list is : " + str(test_list))
# checking for spaces using regex
# not including row if any string has space
res = [row for row in test_list if not any(
bool(re.search(r"\s", ele)) for ele in row)]
# printing result
print("Filtered Rows : " + str(res))
输出:
原列表为:[['gfg is '，' best']，['gfg '，' good']，['gfg is cool']，['love '，' gfg']] 过滤行:['gfg '，' good']，['love '，' gfg']]
方法 2:使用 滤镜()+lambda+any()+regex
在本例中，我们使用 filter()和 lambda 函数执行过滤任务，其余所有功能都与上述方法类似。
Python 3
# Python3 code to demonstrate working of
# Filter rows without Space Strings
# Using filter() + lambda + any() + regex
import re
# initializing list
test_list = [["gfg is", "best"], ["gfg", "good"],
["gfg is cool"], ["love", "gfg"]]
# printing original list
print("The original list is : " + str(test_list))
# checking for spaces using regex
# not including row if any string has space
res = list(filter(lambda row: not any(bool(re.search(r"\s", ele))
for ele in row), test_list))
# printing result
print("Filtered Rows : " + str(res))
输出:
原列表为:[['gfg is '，' best']，['gfg '，' good']，['gfg is cool']，['love '，' gfg']] 过滤行:['gfg '，' good']，['love '，' gfg']]
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