Python |查找列表中给定元素的频率之和
给定两个包含整数的列表，任务是找出第一个列表元素在第二个列表中的频率之和。
示例:
Input: list1 = [1, 2, 3]
list2 = [2, 1, 2, 1, 3, 5, 2, 3]
Output: 7
Explanation:
No of time 1 occurring in list2 is :2
No of time 2 occurring in list2 is :3
No of time 3 occurring in list2 is :2
Sum = 2+3+2 = 7
以下是实现上述任务的一些方法。
方法#1: 使用sum()
# Python code to find sum of frequency of
# element of first list in second list.
# List initialization
Input1 = [1, 2, 3]
Input2 = [2, 1, 2, 1, 3, 5, 2, 3]
# Using sum
Output = sum(Input2.count(elem) for elem in Input1)
# Printing output
print("Initial list are:", Input1, Input2)
print("Frequency is:", Output)
Output:
Initial list are: [1, 2, 3] [2, 1, 2, 1, 3, 5, 2, 3]
Frequency is: 7
方法二:使用sum()``Counter()
from collections import Counter
# List initialization
Input1 = [1, 2, 3]
Input2 = [2, 1, 2, 1, 3, 5, 2, 3]
temp = Counter(Input2)
Output = sum(temp[x] for x in Input1)
# Printing output
print("Initial list are:", Input1, Input2)
print("Frequency is:", Output)
Output:
Initial list are: [1, 2, 3] [2, 1, 2, 1, 3, 5, 2, 3]
Frequency is: 7
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