通过匹配元组列表中的第二个元组值进行 Python 分组
原文:https://www . geesforgeks . org/python-按匹配分组-第二元组-元组列表中的值/
给定元组列表，任务是通过匹配元组中的第二个元素来对元组进行分组。我们可以通过使用字典检查每个元组中的第二个元素来实现这一点。
示例:
Input : [(20, 80), (31, 80), (1, 22), (88, 11), (27, 11)]
Output: {80: [(20, 80), (31, 80)],
11: [(88, 11), (27, 11)],
22: [(1, 22)]}
Input : [(20, 'Geek'), (31, 'Geek'), (88, 'NotGeek'), (27, 'NotGeek')]
Output: {'NotGeek': [(88, 'NotGeek'), (27, 'NotGeek')],
'Geek': [(20, 'Geek'), (31, 'Geek')]}
代码#1:
# Python program to group tuples by matching
# second tuple value in list of tuples
# Initialisation
Input = [(20, 80), (31, 80), (1, 22), (88, 11), (27, 11)]
Output = {}
for x, y in Input:
if y in Output:
Output[y].append((x, y))
else:
Output[y] = [(x, y)]
# Printing Output
print(Output)
Output:
{80: [(20, 80), (31, 80)], 11: [(88, 11), (27, 11)], 22: [(1, 22)]}
代码#2:
# Python program to group tuples by matching
# second tuple value in list of tuples
# Initialisation
Input = [(20, 'Geek'), (31, 'Geek'), (88, 'NotGeek'), (27, 'NotGeek')]
Output = {}
for x, y in Input:
if y in Output:
Output[y].append((x, y))
else:
Output[y] = [(x, y)]
# Printing Output
print(Output)
Output:
{'NotGeek': [(88, 'NotGeek'), (27, 'NotGeek')],
'Geek': [(20, 'Geek'), (31, 'Geek')]}
版权属于：月萌API www.moonapi.com，转载请注明出处
