Python |查找元组中的列表数量
给定一个列表元组，任务是找到一个元组中的列表数。这是一个非常基本的问题，但在进行一些实用应用时会很有用。
方法#1:使用镜头T3】
# Python code to find number of list in a tuple
# Initial list
Input1 = ([1, 2, 3, 4], [5, 6, 7, 8])
Input2 = ([1, 2], [3, 4], [5, 6])
Input3 = ([9, 8, 7, 6, 5, 4, 3, 2, 1], [1, 2, 3])
# Using len to find no of list in tuple
Output1 = len(Input1)
Output2 = len(Input2)
Output3 = len(Input3)
# Printing
print("Initial list :")
print(Input1)
print("No of list in tuples are :")
print(Output1)
print("\n")
print("Initial list :")
print(Input2)
print("No of list in tuples are :")
print(Output2)
print("\n")
print("Initial list :")
print(Input3)
print("No of list in tuples are :")
print(Output3)
print("\n")
Output:
Initial list :
([1, 2, 3, 4], [5, 6, 7, 8])
No of list in tuples are :
2
Initial list :
([1, 2], [3, 4], [5, 6])
No of list in tuples are :
3
Initial list :
([9, 8, 7, 6, 5, 4, 3, 2, 1], [1, 2, 3])
No of list in tuples are :
2
方法 2:使用功能和实例
# Python code to find number of list in a tuple
# Using find function
def find(Input):
if isinstance(Input, list):
return 1
else:
return len(Input)
# List initialization
Input1 = ([1, 2, 3, 4], [5, 6, 7, 8])
Input2 = ([1, 2], [3, 4], [5, 6])
Input3 = ([9, 8, 7, 6, 5, 4, 3, 2, 1])
# using find
Output1 = find(Input1)
Output2 = find(Input2)
Output3 = find(Input3)
# printing
print("Initial list :")
print(Input1)
print("No of list in tuples are :")
print(Output1)
print("\n")
print("Initial list :")
print(Input2)
print("No of list in tuples are :")
print(Output2)
print("\n")
print("Initial list :")
print(Input3)
print("No of list in tuples are :")
print(Output3)
print("\n")
Output:
Initial list :
([1, 2, 3, 4], [5, 6, 7, 8])
No of list in tuples are :
2
Initial list :
([1, 2], [3, 4], [5, 6])
No of list in tuples are :
3
Initial list :
[9, 8, 7, 6, 5, 4, 3, 2, 1]
No of list in tuples are :
1
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