Python groupby 方法删除所有连续的重复项
原文:https://www . geesforgeks . org/python-group by-method-remove-continuous-duplicates/
给定一个字符串，删除所有连续的重复项。
示例:
Input : aaaaabbbbbb
Output : ab
Input : geeksforgeeks
Output : geksforgeks
Input : aabccba
Output : abcba
这个问题我们已经有了解决方案，请参考从字符串链接中删除所有连续的重复项。我们可以使用 itertools.groupby() 方法在 python 中快速解决这个问题。
itertools.groupby(iterable，key[optional])在 Python 中是如何工作的？
Group by 方法接受两个输入一个是可迭代(列表、元组、字典)第二个是计算可迭代中每个元素的键的键函数。它返回分组项的关键字和可重复项。如果键函数未指定或为“无”，则键默认为标识函数，并返回元素不变。例如，
numbers = [1, 1, 1, 3, 3, 2, 2, 2, 1, 1]
import itertools
for (key,group) in itertools.groupby(numbers):
print (key,list(group))
输出:
(1, [1, 1, 1])
(3, [3, 3])
(2, [2, 2])
(1, [1, 1])
# function to remove all consecutive duplicates
# from the string in Python
from itertools import groupby
def removeAllConsecutive(input):
# group all consecutive characters based on their
# order in string and we are only concerned
# about first character of each consecutive substring
# in given string, so key value will work for us
# and we will join these keys without space to
# generate resultant string
result = []
for (key,group) in groupby(input):
result.append(key)
print (''.join(result))
# Driver program
if __name__ == "__main__":
input = 'aaaaabbbbbb'
removeAllConsecutive(input)
参考文献: https://docs.python.org/3/library/itertools.html
输出:
ab
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