Python |基于值将元组分组到列表中
原文:https://www . geesforgeks . org/python-group-tuple-to-list-based-on-value/
有时，在使用 Python 元组时，我们会遇到一个问题，即我们需要根据分配给它的值将元组元素分组到嵌套列表中。这在许多分组应用中非常有用。让我们讨论执行这项任务的某些方法。
方法一:使用itemgetter() +列表理解+groupby()+T3】
上述功能的组合可用于执行该任务。在这种情况下，我们使用itemgetter()访问值，并且使用groupby()和列表理解来执行分组逻辑。
# Python3 code to demonstrate working of
# Group tuple into list based on value
# using itemgetter() + list comprehension + groupby()
from operator import itemgetter
from itertools import groupby
# initialize list
test_list = [(1, 4), (2, 4), (6, 7), (5, 1), (6, 1), (8, 1)]
# printing original list
print("The original list : " + str(test_list))
# Group tuple into list based on value
# using itemgetter() + list comprehension + groupby()
res = [[i for i, j in temp]\
for key, temp in groupby(test_list, key = itemgetter(1))]
# printing result
print("The list after grouping by value : " + str(res))
Output :
The original list : [(1, 4), (2, 4), (6, 7), (5, 1), (6, 1), (8, 1)]
The list after grouping by value : [[1, 2], [6], [5, 6, 8]]
方法二:使用map() + itemgetter() + groupby() +列表理解
这个方法类似于上面的方法，唯一的区别是我们选择了 map 来形成关键字，作为嵌套列表来形成新的结果列表。
# Python3 code to demonstrate working of
# Group tuple into list based on value
# using map() + itemgetter() + groupby() + list comprehension
from operator import itemgetter
from itertools import groupby
# initialize list
test_list = [(1, 4), (2, 4), (6, 7), (5, 1), (6, 1), (8, 1)]
# printing original list
print("The original list : " + str(test_list))
# Group tuple into list based on value
# using map() + itemgetter() + groupby() + list comprehension
res = [list(map(itemgetter(0), temp))
for (key, temp) in groupby(test_list, itemgetter(1))]
# printing result
print("The list after grouping by value : " + str(res))
Output :
The original list : [(1, 4), (2, 4), (6, 7), (5, 1), (6, 1), (8, 1)]
The list after grouping by value : [[1, 2], [6], [5, 6, 8]]
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