Python 中的 hex()函数
【hex()函数是 Python3 中的内置函数之一，用于将一个整数转换为其对应的十六进制形式。
语法:
hex(x)
Parameters :
x - an integer number (*int* object)
Returns : Returns hexadecimal string.
错误和异常:
TypeError : Returns TypeError when anything other than
integer type constants are passed as parameters.
代码#1 : 说明 hex() 功能的使用。
Python 3
# Python3 program to illustrate
# hex() function
print("The hexadecimal form of 23 is "
+ hex(23))
print("The hexadecimal form of the "
"ascii value is 'a' is " + hex(ord('a')))
print("The hexadecimal form of 3.9 is "
+ float.hex(3.9))
输出:
The hexadecimal form of 23 is 0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1
代码#2: 演示浮点值作为参数传递时的类型错误。
Python 3
# hex() accepts only integer values as parameters
print("The hexadecimal form of 11.1 is "
+ hex(11.1))
'''
# The hexadecimal conversion of floating
# point integers can be done using the
# function float.hex()
print("The hexadecimal form of 11.1 is "
+ float.hex(11.1))
# Output :
# The hexadecimal form of 11.1 is 0x1.6333333333333p+3
# Similarly, float.hex() throws a TypeError
# when integer values are passed in it.
'''
输出:
Traceback (most recent call last):
File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in
print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer
应用: hex()用于所有的标准转换。例如十六进制到十进制、十六进制到八进制、十六进制到二进制的转换。
代码#3 :
Python 3
# TypeConversion from decimal with base 10
# to hexadecimal form with base 16
# Taking input from user
# an integer with base 10
number = int(input("Enter a number with base 10\n"))
# The choices present to the user
print("a. Decimal to Hexadecimal ")
print("b. Decimal to Octal")
print("c. Decimal to Binary")
# taking user input
print("Enter your choice :- ")
choice = input()
# Running a variable choice
# Hexadecimal form if choice
# is set to 'a'
if choice is 'a':
# lstrip helps remove "0x" from the left
# rstrip helps remove "L" from the right,
# L represents a long number
print("Hexadecimal form of " + str(number) +
" is " + hex(number).lstrip("0x").rstrip("L"))
if choice is 'b':
# Octal representation is done
# by adding a prefix "0o"
print("Octal form of " + str(number) +
" is " + oct(number).lstrip("0o").rstrip("L"))
if choice is 'c':
# Binary representation is done by
# the addition of prefix "0b"
print("Binary form of " + str(number) +
" is "+bin(number).lstrip("0b").rstrip("L"))
输出:
输入变量 a)
Enter a number with base 10
123
a. Decimal to Hexadecimal
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:-
a
Hexadecimal form of 123 is 7b
输入变量 b)
Enter a number with base 10
123456789
a. Decimal to Hexadecimal
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:-
a
Hexadecimal form of 123456789 is 75bcd15
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